<?xml-stylesheet type="text/xsl" href="https://community.element14.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/"><channel><title>Back to Karnaugh</title><link>/members-area/personalblogs/b/blog/posts/back-to-karnaugh</link><description>Back in school I had a few courses in digital electronics, so Karnaugh maps were not something alien to me. Unfortunately, my life experience never took me down a path where I had to simplify Boolean equations. A current software development pro...</description><dc:language>en-US</dc:language><generator>Telligent Community 12</generator><item><title>RE: Back to Karnaugh</title><link>https://community.element14.com/members-area/personalblogs/b/blog/posts/back-to-karnaugh</link><pubDate>Mon, 04 Aug 2014 19:37:13 GMT</pubDate><guid isPermaLink="false">93d5dcb4-84c2-446f-b2cb-99731719e767:d6b01b14-b744-4405-bc87-69220deb889b</guid><dc:creator>SGarciaV</dc:creator><slash:comments>1</slash:comments><description>&lt;p&gt;Thanks for the remarks all.&lt;/p&gt;&lt;p&gt;&amp;nbsp;&lt;/p&gt;&lt;p&gt;Shabaz, your function will work as well. I guess I am just in the habit of testing for valid results, not invalid. Your code reflects a conversion of my formula from sum of products (/a/b + c) to product of sums (a+b) AND /c. The production code will contain enough of an explanation to allow me and anyone else to understand what the function is doing. I have way too many projects and will most likely not remember this function within a few months.&lt;/p&gt;&lt;p&gt;&amp;nbsp;&lt;/p&gt;&lt;p&gt;Mcb1. In boolean algebra, the &amp;quot;+&amp;quot; operator is commonly used to denote an OR operation as a dot at mid height represents a AND operation. Having the formula /a/b + c is the same as saying not a AND not b OR c. Perhaps a bit clearer would be ((not a) AND (not b)) OR c. I hope I&amp;#39;ve answered your question since I am not sure if I understood it. Salvador&lt;/p&gt;&lt;img src="https://community.element14.com/aggbug?PostID=18121&amp;AppID=293&amp;AppType=Weblog&amp;ContentType=0" width="1" height="1"&gt;</description></item><item><title>RE: Back to Karnaugh</title><link>https://community.element14.com/members-area/personalblogs/b/blog/posts/back-to-karnaugh</link><pubDate>Sat, 02 Aug 2014 02:11:53 GMT</pubDate><guid isPermaLink="false">93d5dcb4-84c2-446f-b2cb-99731719e767:d6b01b14-b744-4405-bc87-69220deb889b</guid><dc:creator>mcb1</dc:creator><slash:comments>1</slash:comments><description>&lt;p&gt;Never did study that, and during my training the Logic course was the worst.&lt;/p&gt;&lt;p&gt;&amp;nbsp;&lt;/p&gt;&lt;p&gt;Looking at your truth table it seems that whenever c=1 its valid or when a,b and c = o its valid.&lt;/p&gt;&lt;p&gt;&amp;nbsp;&lt;/p&gt;&lt;p&gt;You might want to expand on how you got from the formula to the expression ( ie how does &amp;#39;+ c&amp;#39;&amp;nbsp; translate to an OR)&lt;/p&gt;&lt;p&gt;&amp;nbsp;&lt;/p&gt;&lt;p&gt;&amp;nbsp;&lt;/p&gt;&lt;p&gt;very useful thanks for sharing&lt;/p&gt;&lt;p&gt;Mark&lt;/p&gt;&lt;img src="https://community.element14.com/aggbug?PostID=18121&amp;AppID=293&amp;AppType=Weblog&amp;ContentType=0" width="1" height="1"&gt;</description></item></channel></rss>