/members-area/personalblogs/b/blog/posts/how-equalization-works-in-10x-passive-probesWe&#39;ve been discussing 10x passive probes and their inner workings; our last post covered all the ways in which a 10x passive probe is apt to be a liability. They&#39;d be basically unusable for any measurements at all but for one attribute: their...en-USTelligent Community 12https://community.element14.com/members-area/personalblogs/b/blog/posts/how-equalization-works-in-10x-passive-probesWed, 13 Feb 2019 11:22:13 GMT93d5dcb4-84c2-446f-b2cb-99731719e767:1097f5aa-d54c-40cc-b14d-0965abe1ff84jc20480<p>Thank you for posting this - very nicely done.</p><p>&nbsp;</p><p>I&#39;ve read the explanation before a couple of times but this is the first time I&#39;ve seen it supported by the plots you show. Although in theory we can all work out the way the impedance at the input varies with frequency, the plot really does emphasise how the capacitive reactance causes it to drop with frequency. At 1MHz we essentially have a 20k probe and at 10MHz a 2k one, which is a long way from the 10M that we all imagine when we first start out and are new to electronics. It&#39;s easy to see from the graph how a &#39;scope probe can have an effect on something like a sensitive analog oscillator circuit, even at frequencies of a few hundred kilohertz.</p><p>&nbsp;</p><p>It&#39;s also useful seeing where the effect of the ground lead inductance comes into play.</p><p>&nbsp;</p><p>Looking forward to hearing your explanation of the &#39;Very special cable&#39;.</p><img src="https://community.element14.com/aggbug?PostID=6500&AppID=293&AppType=Weblog&ContentType=0" width="1" height="1">