Servos and coding

Reversing them is just a matter of switching the values around and decrementing rather than incrementing. As such, it will look something like:

void loop ()
{
     for(int pos=180; pos > 0; pos--)
     {
          myservo.write(pos);
          myservo1.write(pos);
          delay(15);
     }
}

For your other piece of code, it may be worth inserting a delay between each statement. Telling a servo to move to a position takes a small amount of time and as a result will not happen at the same time, there will always be a little delay between the two. This is why on the example code, it has delay(15) after each write.

Hope this helps!

well I want the servos doing this:

servo 1 - from 0 to 180

servo 2 -from 180 to 0

no delay between them

what would that look like?

I would use something like this. Having no delay is relatively hard to do due to the write delays. PWM sadly isn't an instant thing. The best you can hope for (Without having a fancy distributed system) is reducing it to a tiny display that you won't notice too much.

void loop()
{
     int pos = 0; //Number of times the loop has run
     int serPos1 = 0; //Position of servo1
     int serPos2 = 180; //Position of servo2

     while(pos < 180)              //While the loop has been done less than 180 times...
     {
          myservo.write(serPos1);
          myservo1.write(serPos2);
          serPos1++;               //Increment position of servo1
          serPos2--;               //Decrement position of servo2
          pos++;                   //Increment loop counter.

          delay(15);               //Write delay. Can always try without, but no guarantees it would work
     }
}

This is by no means the only way to do it, but should give you an idea.

Thanks for the idea! I will try that.