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Ohms law

salesm21

To anyone who can help,

I have been recently wondering about something rather simple. Why is it in ohms law does R=V/I & I=V/R? This means that voltage is proportional to both resistance and current? I know the more voltage you have the more energy is given to each coloumb of charge but why is it that when 1 volt of energy is in 1 C of charge is there 1 ohm?

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  • This means that voltage is proportional to both resistance and current

    Without sidetracking into the science (it hurts my head), the formula allows you to calculate the missing item when you know the other two.

    At some point someone worked out the maths and they all aligned.

     

    I tend to like the water theories.

    If you have a river that falls a long way that is the voltage (V)

    The river could flow a lot of water or there is very little to slow it down/hinder the flow (R)

    The amount of water flowing depends on both the amount of fall (V) and the resistance/hinderance (R)

     

    It not possible to have lots of flow when the resistance is high, or indeed when the fall is small

     

    Energy is a different equation or relationship, like the equations for work, etc.

     

     

    Mark

Reply

  • This means that voltage is proportional to both resistance and current

    Without sidetracking into the science (it hurts my head), the formula allows you to calculate the missing item when you know the other two.

    At some point someone worked out the maths and they all aligned.

     

    I tend to like the water theories.

    If you have a river that falls a long way that is the voltage (V)

    The river could flow a lot of water or there is very little to slow it down/hinder the flow (R)

    The amount of water flowing depends on both the amount of fall (V) and the resistance/hinderance (R)

     

    It not possible to have lots of flow when the resistance is high, or indeed when the fall is small

     

    Energy is a different equation or relationship, like the equations for work, etc.

     

     

    Mark

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