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  • ohms law
Related

Ohms law

salesm21
salesm21 over 7 years ago

To anyone who can help,

I have been recently wondering about something rather simple. Why is it in ohms law does R=V/I & I=V/R? This means that voltage is proportional to both resistance and current? I know the more voltage you have the more energy is given to each coloumb of charge but why is it that when 1 volt of energy is in 1 C of charge is there 1 ohm?

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  • jw0752
    jw0752 over 7 years ago +8
    Hi Mitchell, Let's imagine that we have a perfect source of 10 volts with no internal resistance. What ohms law does is give us a formula for calculating the current in a circuit if we know the resistance…
  • jw0752
    jw0752 over 7 years ago in reply to gdstew +8
    Hi Gary, While I tend to agree with you, if one really has a scientific thought process we have to leave open the possibilities. The scientific community went 200 years believing that they had things all…
  • mcb1
    mcb1 over 7 years ago in reply to michaelkellett +8
    michaelkellett I'm with you. I've managed all these years without worrying about the unseen things causing it to happen. Quite frankly I don't really care which way they actually move, as long as something…
  • jw0752
    jw0752 over 7 years ago

    Hi Mitchell,

     

    Let's imagine that we have a perfect source of 10 volts with no internal resistance. What ohms law does is give us a formula for calculating the current in a circuit if we know the resistance of that circuit or the resistance of a circuit if we know the current. You can not think of Ohm's law outside the context of a circuit. If we have the 10 volt supply and we put an ammeter in the circuit and we measure 5 amps of current we can use the Ohms law to determine that the circuit has 2 Ohms of resistance. If on the other hand we put a 6 Ohm resistor across the 10 volts we will find that 1.66 Amps are flowing if we were to measure it. Let me know if I misunderstood your question.

     

    John

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  • gecoz
    gecoz over 7 years ago

    Hi Mitchell,

     

    I think your doubts stem from the confusion between Potential Energy (measured in Joule) and difference of Potential between 2 points (measured in Volt).

     

    When a Potential of 1 V is applied to a charge of 1 Coulomb, you have a potential energy of 1 Joule in this system. This is static energy, stored in the system (if you think of mechanics, it is like when you hold an object in your hand: the object has potential energy, due to its weight, its position and the gravity), and in this situation the charge is not moving.

     

    Once you let the charge move, by connecting the 2 points and creating a circuit (i.e. you let the object in your hand go, and the object falls), the energy is transformed in work, which will make the charge flow into the circuit. The flow of charge in the unit of time is your current (measured in Ampere).

     

    When you are in this situation (potential applied to a circuit, giving rise to a current flow), then you can define how "easy" or "hard" this charge can flow in the circuit (i.e. how much charge can flow, depending on physical properties of the circuit): this is what Ohm's law will tell you. Resistance measures just that.

     

    jw0752 example explains perfectly how Ohm's law works in a circuit.

     

    I hope this helps,

    Fabio.

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  • DAB
    DAB over 7 years ago

    Hi Mitchell,

     

    You need to understand the issues involved.

    Charge flow occurs when you establish a potential (EMF measured as voltage) through a conductor.

    Every conductor has some level of resistance due to impurities in the material.

    As the charge flows through the conductor, the mass/energy is passed from atom to atom.  The conductor atoms are arranged in a crystal structure and can easily pass each photon from atom to atom.  When the photons reach an atom of different type (impurity), that atom may emit a photon of a different type (usually IR), which reduces the amount of charge through the conductor.  That is why wires get warm when you pass a lot of current through them.  Their residual resistance caused by the impurities causes some of the current to be released as IR photons.

     

    In a superconductor, the atoms are all at their minimum energy state, which allows them to pass the photons between atom without emitting any IR photons, but the impure atoms will release photons of higher frequencies.  So there is still some loss, but in general, even the impure atoms will mostly pass the charge with less loss.

     

    DAB

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  • gdstew
    gdstew over 7 years ago in reply to DAB

    Not photons, electrons. And while impurities do cause resistance I'm fairly certain that electrons bouncing off the atoms of the conductor,

    and imparting energy on those atoms in the form of heat is the main source of resistance in "pure" conductors.

     

    P.S. It was Ben Franklin that first postulated that electric current was the flow of "particles" in conductors. It was over a hundred

    years later that the electron was finally discovered as that particle in experiments with early cathode ray tubes.

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  • salesm21
    salesm21 over 7 years ago in reply to gecoz

    Fabio,

    So in order to make electrons flow you want to make it where one point is positive and one point is negative right? So is voltage really a measurement of the positive/negative ions that are placed at opposite ends of a circuit? Because it takes energy to separate charges from neutral atoms is voltage a measurement of the amount of energy stored in the process of separating the electrons? Then when the two points are connected this makes a path for charges to equalize. How dopes ohms law take into account the physical properties of the circuit?

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  • salesm21
    salesm21 over 7 years ago in reply to jw0752

    John,

    So I think you did. You reasoning was that ohms law is a group of mathematical formulas that are used to help us calculate circuit quantities as well as understand and quantify relationships between different electrical phenomenon. So your saying I have to look at Volt/current & resistance in separate ways then as a whole?

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  • jw0752
    jw0752 over 7 years ago in reply to salesm21

    Hi Mitchell,

    In any given circuit there is a physical relationship between Voltage, Resistance, and Current. Ohm's law models this relationship mathematically. Theoretically it is possible to have a voltage without a current if there is an infinite resistance. We can not have a current without a voltage. Different materials become resistances when they become part of a circuit and convert the energy of the electron flow into heat. Since I didn't understand your last question I have tried to rephrase my previous response.

    John

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  • michaelkellett
    michaelkellett over 7 years ago

    There is a useful Wiki article here. It goes into more detail (and history) than you need but is interesting.

     

    You don't need to think about photons, electrons, ions or such stuff to understand and design perfectly good electronic circuits.

     

    I visualise circuits in terms of conventional current flow all the time - I don't give damn which way the electrons are going or how fast they actually move.

     

    https://en.wikipedia.org/wiki/Ohm%27s_law#History

     

    MK.

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  • gecoz
    gecoz over 7 years ago in reply to salesm21

    Hi Mitchell,

     

    in general, I am all for simplifying things, in order to make easier to grasp the concepts. Sometimes, though, you need to formally define entities and relationships, otherwise you end up with a lot of confusion. So, with this in mind, I will try answering your questions the best I can, while also keeping as simple as I can.

     

    In order to have a current flowing in a conductor/circuit, it is enough that the ends of such conductor are connected to points at different potential, not necessarily to a positive and a negative. The fact that we mark the ends as + and - is a convention that has been established, just like the conventional flow for the current is established to be from positive voltage point to the negative one (while, actually, the electrons move the opposite way). Applying a voltage at the ends, let's say by connecting a battery to the conductor, you are creating a condition where there is a difference in potential.

     

    Voltage (difference of potential between 2 points) does not represent a measurement of the quantity of positive/negative charge stored at the two ends, but rather a measurement of how much work is needed to move one unit of charge from one end to the other. In a battery, for example, the voltage of its poles does not depend on how much charge it has stored, but it is defined by the chemical elements used to build it (for the chemical reaction). It is the energy of a battery that tells you how much charge is stored in it (anyway, as you said, electrically the battery is neutral, because the amount of positive charge equals the amount of negative ones).

     

    When you apply a voltage to the ends of a conductor, you create an electric field between the two ends. While normally, in a conductor, free electrons move randomly in all directions, with no net flow of charges (no current), when the electric field is applied, an electric force is applied to the free electrons, forcing them to ordinately move, following the direction of the field, and so generating a net flow of charge - the current.

     

    The physical structure of the conductor determines how much current can flow:  while moving, some of the electrons collide with the conductor's ions. In the collision, the electron loses part of its kinetic energy, which is transferred to the conductor's ion. The ions of the conductor are bonded together, so this transferred energy will cause them to vibrate more (an increase in vibration means an increase in temperature for the conductor). Ultimately, the "resistivity" of an object is a measure of how much electrons are "taken out" by the collisions, and so how much the conductor "resists" to the flow of charges.

     

    The physical properties of the conductor are taken into account with the value of the resistance R itself. In particular, for any material we can define a property called resistivity, which only depends on the physical characteristics of the material. Then, the resistance of an object R is directly proportional to the resistivity and the lenght of the object, and inversely proportional to the cross-section area of the object. In Ohm's law, R does not depend on either V or I, but it is a constant, which means that, for an obkect of know resistance R, any change in the voltage across it will result in a change is the current flowing through it.

     

    I hope this helps,

    Fabio.

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  • DAB
    DAB over 7 years ago in reply to gdstew

    Hi Gary,

     

     

    No, I really meant photons.  I have done extensive research into subatomic physics over the last nine years and I have found that there is NO experimental evidence to support the idea that electrons are either a part of atoms or flow between atoms in electronic devices.

     

    The mathematical proofs we present in my book "Reverse Engineering The Universe" show that the atom is more likely to have a shell of captured photons instead of the accepted orbiting electrons.  The photon model shows that you get a better understanding of how mass/charge flows between atoms to support all of the macro-level attributes associated with electron flow.

     

    My photon flow model works very well to explain how and why V = I*R works at all levels from sub-atomic to Universe level events.

     

    I know this idea runs contrary to everything everyone has been told or taught, but so far my models do a much better job of explaining actual electronic measurements at the atom and subatomic level.

     

    DAB

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