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Member's Forum Figuring out current draw
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Related

Figuring out current draw

inavitech
inavitech 29 days ago

So I'm working on a project with an unknown and not sure how to figure out what I need to know. My customer wants new USB chargers and I'm trying to figure out if the circuit will handle the load of the new chargers. The current charger is a single USB A. Input is 28VDC, output is 5VDC at 3 AMPS, 15 WATTS. Not sure what formula to use to compute current draw on the input side. My new chargers consume 1.25AMPS each.

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  • kmikemoo
    kmikemoo 29 days ago +1
    There really isn't a formula that is going to give you the answer that you seek. " P = (E * I) + losses " isn't much help. If you measure your input current draw, you can figure out what those losses are…
  • michaelkellett
    michaelkellett 28 days ago in reply to dang74 +1
    And you need to take account of switch on surges - it's often very hard to get good information from suppliers.. In cases like this you need to choose the closest replacement you can find and do some…
  • michaelkellett
    michaelkellett 23 days ago in reply to inavitech +1
    If this is on a plane won't it need the full certification stuff ? MK
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  • kmikemoo
    kmikemoo 29 days ago

    There really isn't a formula that is going to give you the answer that you seek.  "P = (E * I) + losses" isn't much help.
    If you measure your input current draw, you can figure out what those losses are but even circuit simulators aren't going to be able to predict what you will really lose across the device.  Your load will also likely exceed 1.25A from time to time.  28V to 5v sounds like adding USB charging to industrial equipment.  If you put a USB outlet there... people will use it for all sorts of things.

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  • kmikemoo
    kmikemoo 29 days ago

    There really isn't a formula that is going to give you the answer that you seek.  "P = (E * I) + losses" isn't much help.
    If you measure your input current draw, you can figure out what those losses are but even circuit simulators aren't going to be able to predict what you will really lose across the device.  Your load will also likely exceed 1.25A from time to time.  28V to 5v sounds like adding USB charging to industrial equipment.  If you put a USB outlet there... people will use it for all sorts of things.

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