Sound sketch

Sorry, I should have added the "sirenOn" initiated the buzzer.

Double check the wire actually goes from A3 and that it has no internal hidden open. 

Keith

From your description the buzzer is an external sounder/speaker.

If its a device you place volts across and it makes noise, then you need to treat it as a digital output with a random amount of ON time as you wish.

If its more like a speaker then I think you need 'tone', which generates a square wave at a certain frequency.

http://arduino.cc/en/Reference/Tone

mark

In my mind, there is a huge difference between a 'single beep' and a 'single click'.  I hope your understanding is correct, Mark B.

Thanks. I switched pins to D3 and edited the analog to digital.  The sketch is working. Well, not exactly as it should. Firstly, there is a long, ten second delay after running through the sounds before starting once again.  And, when the sensor goes below the threshold, the sketch continues to the end before stopping.  To stop immediately, is an interrupt necessary? I have no experience with interrupts but will dive into it if advised this is the solution.  Thanks.

int siren = 3;

long randOn =0;

long randOff =0;

int snd1 = 5;

int snd2 = 6;

int snd3 = 7;

int snd4 = 8;

int snd5 = 9;

int sensorPin = A0;

int sensorValue = 0;

void setup(){

  pinMode(drummer, OUTPUT);

  pinMode(siren, OUTPUT);

  randomSeed (analogRead (0));

  pinMode(snd1, OUTPUT);

  pinMode(snd2, OUTPUT);

  pinMode(snd3, OUTPUT);

  pinMode(snd4, OUTPUT);

  pinMode(snd5, OUTPUT);

  digitalWrite(snd1,LOW);

  digitalWrite(snd2,LOW);

  digitalWrite(snd3,LOW);

  digitalWrite(snd4,LOW);

  digitalWrite(snd5,LOW);

  Serial.begin(9600);

  delay(500); 

}

void loop()

{

  sensorValue = analogRead(sensorPin);

  Serial.println(sensorValue);

  delay(500);

  if (sensorValue > 15)

  {

    randOn = random (50, 5000);

    randOff = random (1, 900);

    digitalWrite(siren,HIGH);

    delay(randOn);

    digitalWrite(siren,LOW);

    delay(randOff);

    digitalWrite(snd1,HIGH);

    delay(5000);

    digitalWrite(snd1,LOW);

    //delay(3000);

    digitalWrite(snd2,HIGH);

    delay(5000);

    digitalWrite(snd2,LOW);

    // delay(3000);

    digitalWrite(siren,HIGH);

    delay(randOn);

    digitalWrite(siren,LOW);

    delay(randOff);

    digitalWrite(snd3,HIGH);

    delay(5000);

    digitalWrite(snd3,LOW);

    digitalWrite(snd4,HIGH);

    delay(5000);

    digitalWrite(snd4,LOW);

    digitalWrite(snd5,HIGH);

    delay(5000);

    digitalWrite(snd5,LOW);

    //delay(1000);

  }  

  }

Keith

And, when the sensor goes below the threshold, the sketch continues to the end before stopping

A wee comparison for those who might be reading this.

You know a courier/delivery is coming to drop off a parcel at your home, and you are at work.

You call home to ask if it's there, before doing 'something' (4 or 5 tasks) at work that takes 1 hour.

After each 'something' you ring home.

How do you know if the parcel has arrived while you're doing 'something'  ?

You could change your 'if' to 'while' (use Help-reference in the IDE) which effectively keeps 'phoning home' all the time.

The alternative is to add sensorValue = analogRead(sensorPin); and if (sensorValue > 15) at the top of each different sound.

there is a long, ten second delay after running through the sounds before starting once again

I presume you hear the sounds stop and then 10 secs later you see the serial print on the Serial monitor.?

I suggest adding a Serial.println("snd X"); statement before each sound is played to help sort out where it is delayed.

Your last three (snd3,4,5) have 5 sec ON periods, however that doesn't explain the 10 sec delay before starting again.

I would also suggest uncommenting the last delay and dropping the time to 100 or 200mS to let everything settle before it returns to read the analog input.

Mark