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Related

Electrical questions about my robot

braedan
braedan over 9 years ago

Hello Element14 community,

 

I have an amateur understanding of dc electronics but there are a few questions that i haven't found any other threads or discussions on. Probably because i do not know the name of the specific topic.

Forgive me if the answer is obvious, but my first question is on current placement. When i look at a solder less breadboard there are two lanes for a positive and negative voltage from a power supply. Say i have an 6v red led drawing 30ma from the power supply, but is connected to the power supply from the middle of the breadboards power lanes. Now if there is a 6v dc motor connected to the end of the power lanes and is drawing 1.5 amps or so, does the high current affect the led in front of the motor? again: there are 1.5 amps going across the power lanes to the motor at the end, but there is a small led drawing much less current before the motor from the same power source.

 

My second question is about capacitors. I have an array of Sharp (brand) Infrared distance sensors that operate at 5 volts and draw current in sharp bursts rated at around 30-60ma on average. I am planning on wiring all 37 of them to 3, 16 channel multiplexers connected to and Arduino uno that will then read the sensors analog output. (Multiplexer i will be using is the cd74hc4067). I have two questions on this topic, both of them about power connectivity. My first question is about the sensors. On a the sensors website and data sheet they both strongly recommend the use of some sort of capacitor to smooth things out. Please look at the picture attached and help me find the best places to add this extra circuitry. Please keep in mind that the S in the image is the Sharp infrared distance sensor and there are actually 37 sensors and not 3. Second is about the power it self. I was told that the sensor array would take little over 1.5 amps and to be safe i should have a power supply that can supply double the amount of current needed. The problem is that i don't actually need a power supply because i will be running this off a 12v lead acid battery. I'm not sure how to build a voltage regulator that can supply this amount of current (3 amps), if a voltage regulator is what i need. later I found this UBEC DC/DC Step-Down (Buck) Converter 5v @ 3a output on Adafruit but yet again i'm skeptical if it will properly power everything.

 

P.S. - Could a 12v 7aH lead acid battery (specifically this one: https://www.amazon.com/ExpertPower-EXP1270-Rechargeable-Lead-Battery/dp/B003S1RQ2S/ref=sr_1_3?ie=UTF8&qid=1468962932&sr=… )

power this arduino sensor array? Specifically how much am i able to draw from this battery? In the future i plan on building a large robot and i need a battery that will be able to power this sensor array, 3 sub 100watt 24v DC motors, 2 small 24v DC gear motors,a raspberry pi 2b and a 12v dc VGA monitor. I know its allot but they all wont be running at once (mainly the motors) and i also know that i can increase the battery capacity by wiring two or more together in parallel (please correct me if i'm wrong). I'm just asking if this lead acid battery type can discharge the required amount of power with out any battery problems, i don't what any battery fires or an explosion.

 

 

Please write me back and helpful links or answers to my questions!

Thank you for your time!

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Top Replies

  • DAB
    DAB over 9 years ago +3 suggested
    Hi Braedan, You have an ambitious plan and I highly suggest you find someone local to help you with the electronics. Most drive circuits use either a constant current device and or a nice capacitor bank…
  • billpenner
    billpenner over 9 years ago in reply to jw0752 +2 suggested
    just a few thoughts, Braedan: You should definitely use a buck converter for the circuits other than the motors. Since the motors will be 24 volts and other circuits will be 5 Volts, the basic power supply…
  • michaelwylie
    michaelwylie over 9 years ago +2 suggested
    Q1 - Ideally one load does not effect the other. In reality many things can happen. For instance, in your example provided, the motor, or any inductive load, will produce an EMF that will likely feedback…
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  • jw0752
    0 jw0752 over 9 years ago

    Hi Braedan,

    I will think about your other questions. The battery type that you mention is very good for delivering higher current and for the ability to be recharged. 7 aH basically means that you can expect about 7 amps for one hour though reality will probably cut this down. The equipment that you hope to hook up to this battery is quite ambitious. The 100 Watt 12 volt motor alone will draw over 8 amps. I would recommend that you brush up on the math for figuring currents and wattage so you can plan ahead and not waste time and money on batteries or motors that are not compatible. Here is a link to a tutorial on Current and wattage calculations.

     

    http://www.electronics-tutorials.ws/dccircuits/dcp_2.html

     

    John

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  • braedan
    0 braedan over 9 years ago in reply to jw0752

    imageimage

    So.

     

    i have been been doing some research and now know a little more about decoupling. I found this circuit (attached in image) for decoupling an IC. I was wondering if this could be repeated for all 37 IR sensors in place of the IC shown in the circuit. If not could you recommend an new circuit diagram, or maybe better capacitor choices for my needs, thank you!

     

    website:De-coupling

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  • braedan
    0 braedan over 9 years ago in reply to braedan

    Sorry I couldn't post  the images but they are on the website I linked.

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  • jw0752
    0 jw0752 over 9 years ago in reply to braedan

    Hi Braedan,

    Your images came through just fine and the link you used went to a good article on decoupling. Yes if you put your sensors in place of the indicated IC you will provide the decoupling that is recommended. Getting the .1 uF caps close to each Sensor is important and make sure they are across the power supply leads and not attached to any of the signal leads unless recommended by the data sheets. The use of the 47 uF capacitor helps keep the volatge from dipping in the line when the sensor turns on. I would not use an individual 47 uF for each sensor as this will put 1700 uF of capacitance on the power supply rails and this would be excessive. Depending on the power supply or buck converter used to supply the 5 volts I would look at the recommended output capacitor size and provide this amount in 4 or five seperate caps. For example if the converter recommends 100 uF capacitor you could use (5) 22 uF caps. These larger caps should be electrolytic caps and the small 0.1 uF caps ahould be ceramic.

    John

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  • jw0752
    0 jw0752 over 9 years ago in reply to braedan

    Hi Braedan,

    The article that you linked to shows a picture of a small ceramic capacitor labeled 103 but he article talks about a 0.1 uF capacitor. I feel that the 0.1 uF is the correct size and the one marked 103 (which is actually 0.01 uF) may be a little small. Your data sheet may have a recommendation which is best followed.

    John

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  • braedan
    0 braedan over 9 years ago in reply to jw0752

    Hello again John!

     

    Im very concerned about how to safely power my raspberry pi off this battery. Specifically I'm worried about the voltage regulator I may be using will not be able to safely power the pi 2 in the case of the motor noise and loading the main power line. I fear that the out put voltage will fluctuate due to the loading and cause the pi to suffer. do you think that a switch mode regulator will harm the pi? If not here's the link to a video i plan on coping. https://m.youtube.com/watch?v=CEhBN5_fO5o

     

    Thanks!

    -b

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  • jw0752
    0 jw0752 over 9 years ago in reply to braedan

    Hi Braedan,

     

    While I am not probably the expert that you hope I am I will tell you that I think that the proper switching regulator is the only way to go. For one thing switching regulators are much more efficient than linear regulators and as such you will not find as large a portion of your batteries energy going up in waste heat. You may also find that the drop out ( voltage where the regulator output is affected) might be better with the switching regulator. This is why many computer power supplies can run on any voltage from 70 volts to 220 volts without having to move any switches. I am confident that a properly decoupled ( correct capacitors added) switching regulator will work well with your pi 2. Now if I have missed anything the smart guys will swoop in and let us know.

     

    John

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  • jw0752
    0 jw0752 over 9 years ago in reply to braedan

    Hi Braedan,

     

    While I am not probably the expert that you hope I am I will tell you that I think that the proper switching regulator is the only way to go. For one thing switching regulators are much more efficient than linear regulators and as such you will not find as large a portion of your batteries energy going up in waste heat. You may also find that the drop out ( voltage where the regulator output is affected) might be better with the switching regulator. This is why many computer power supplies can run on any voltage from 70 volts to 220 volts without having to move any switches. I am confident that a properly decoupled ( correct capacitors added) switching regulator will work well with your pi 2. Now if I have missed anything the smart guys will swoop in and let us know.

     

    John

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