problem with digital input pins in controlling its output pins.. we really need suggestions...

Question

i have 2 digital input pins(pin16 & pin17 actually i need 4)

just to test if it really gonna work.What i did is that

i just give 5volts or high to these pins as input data

but what happened there is that the 2 digitalOutput pins respectively

seems doesnt do to the conditions i gave it seems it can affect the other condition.

here is a part of my code .

if (digitalRead(16) == LOW )

{ digitalWrite(ledPin7,HIGH);

}

if (digitalRead(17) == LOW )

{ digitalWrite(ledPin6,HIGH);

}

else

digitalWrite(ledPin7,LOW);

digitalWrite(ledPin6,LOW);

,,

what i really want to do there is that

just have 4 inputs(that would be 5volts)

and also give 4 outputs respectively..

we really need Ur suggestions and ideas.. thnx ;d

ntewinkel · Answer

I think it might be the way you are building your if...else statements. Try this way: if (digitalRead(16) == LOW ) { digitalWrite(ledPin7,HIGH); } else { digitalWrite(ledPin7,LOW); } if (digitalRead(17) == LOW ) { digitalWrite(ledPin6,HIGH); } else { digitalWrite(ledPin6,LOW); } It's a good idea to always follow every if and else with a { ... } block, that way you know that everything within the { ... } block will be part of the if, or part of the else. The way you had it set up would always set ledPin6 LOW, because without the curly brackets only the first line after "else" is considered to be part of the else block - the next line is just a line that always gets executed. Hope that helps! Cheers, -Nico

problem with digital input pins in controlling its output pins.. we really need suggestions...

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