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  • Replies 84 replies
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  • communications
  • pinter_electronics_consultants
  • expert
  • radio
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  • chris_pinter
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Have a question about radio or wireless communication?  Ask me!

Chris_Pinter
Chris_Pinter over 15 years ago

This thread has been closed to new questions.

However, we welcome you to Post Your Questionabout Communications in the element14 Community Wireless Communications Technology group. You'll find many fellow members and experts who have just the answer you're looking to find! 

 

Thank You, Your Friends at element14 Community


image

 

Christopher Pinter

As the founder and President of Pinter Electronics Consultants Chris has been instrumental in developing the business from its inception in 2005 to its current status.  He has over 15 years of experience in radio and wireless communication hardware design and product development. Chris graduated from the Okanagan University with a diploma in Electronic Engineering Technology and the British Columbia Institute of Technology with a Bachelor of Technology in Electronics.

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  • Former Member
    Former Member over 15 years ago

    hi i want to know  how i connect two or more office located at different places with radio or wireless communication.

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  • Chris_Pinter
    Chris_Pinter over 15 years ago in reply to Former Member

    Hello Amalngg,

     

    Wifi was specifically designed for this application.   You want to look at 802.11A devices between buildings.  This protocal operates at 5.8GHz and is very line of sight...so you will not get a lot of interference as long as you use a directional antenna.

     

    For access to the wireless network within your building you want to use 802.11G or N devices to get the maximum bandwidth and user access.

     

    I hope this helps.

     

    Chris Pinter

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  • Former Member
    Former Member over 14 years ago in reply to Chris_Pinter

    Sir,

         I have an issue deciding the value of speed while calculating the wavelength of a signal. The formula I am using is lambda = c/f where 'f' is the frequency and 'c' is the speed. The issue is, while calculating the wavelength of a signal with frequency, say, 10KHz, what should be the value of speed that I should consider? So far I have read in many books and also on the internet that the speed I should consider is the speed of light which I find as wierd because the speed of signals in the frequency range 20Hz to 20KHz is about 340 m/s in air since these are sound waves. So considering the speed of light for finding the wavelength of a much slower signal is something I dont understand.

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  • Former Member
    Former Member over 13 years ago in reply to Former Member

    It depends on your detector.

     

    10KHz is just about the lowest frequency anyone ever calls "radio frequency." (Yes, some Navys use far lower frequencies, even in the single digits, for underwater, around the world, submarine communications, but that is rather, um, "special."

     

    But 10KHz is also within the range of human hearing. That begs the question...

     

    What method are you using to create and detect these frequencies? If you create it with an audio transducer ("a speaker" (a fairly small one)), then you are creating a mechanical wave ("a sound wave" in this case) which will travel at roughly 340 m/s in air (dependent on temperature, etc.) and you will detect it with something like a microphone. On the other hand, if you are creating your wave with an antenna then you will be creating a electromagnetic wave which will travel at 3x10^8 m/s and you will receive it with another antenna (another very long one).

     

    The general equation relating speed of a wave and wavelength is lambda = v / f. This is altered slightly into the form you provided, lambda = c / f for the special case of electromagnetic radiation (radio waves, microwaves, light, x-rays, gamma rays). In this case c (speed of light = 3x10^8 m/s) replaces the more general "v." But when dealing with mechanical waves, for example, sound, you set v equal to the speed of sound in the medium being analyzed. Note that speed of sound in air and water are much different.

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  • Former Member
    Former Member over 13 years ago in reply to Former Member

    It depends on your detector.

     

    10KHz is just about the lowest frequency anyone ever calls "radio frequency." (Yes, some Navys use far lower frequencies, even in the single digits, for underwater, around the world, submarine communications, but that is rather, um, "special."

     

    But 10KHz is also within the range of human hearing. That begs the question...

     

    What method are you using to create and detect these frequencies? If you create it with an audio transducer ("a speaker" (a fairly small one)), then you are creating a mechanical wave ("a sound wave" in this case) which will travel at roughly 340 m/s in air (dependent on temperature, etc.) and you will detect it with something like a microphone. On the other hand, if you are creating your wave with an antenna then you will be creating a electromagnetic wave which will travel at 3x10^8 m/s and you will receive it with another antenna (another very long one).

     

    The general equation relating speed of a wave and wavelength is lambda = v / f. This is altered slightly into the form you provided, lambda = c / f for the special case of electromagnetic radiation (radio waves, microwaves, light, x-rays, gamma rays). In this case c (speed of light = 3x10^8 m/s) replaces the more general "v." But when dealing with mechanical waves, for example, sound, you set v equal to the speed of sound in the medium being analyzed. Note that speed of sound in air and water are much different.

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