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Thermistor problem...

Former Member
Former Member over 10 years ago

I am confused and having trouble converting the Voltage I read to a temperature using this thermistor: http://canada.newark.com/amphenol-advanced-sensors/mc65f103a/ntc-thermistor-10kohm-radial-leaded/dp/95C0606

 

I have tried to decipher the data sheet provided but no avail... any assistance would be great, thanks!

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  • D_Hersey
    D_Hersey over 10 years ago +1
    "Rt/R25 = exp{A + B/T + C/T 2 + D/T 3 } where T = temperature in K" Yeesh, thermistors.
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  • jw0752
    jw0752 over 10 years ago

    Hi Nicholas, You are right that wasn't a very good data sheet. It looked more like a sales flyer. Since it is a thermistor you will have to build it into some sort of a voltage divider and then read the voltage across one of the resistors in the divider circuit. The voltage that you get for a specific temperature will depend on the resistances that you choose to go into the divider. If I were doing it I would use an empirical approach and once I had the divider set up and I was reading the voltage I would put the thermistor in contact with melting ice and read my voltage. This voltage corresponds to 0 degrees C. Next I would calculate the temperature of boiling water for the atmospheric pressure where I live. Then I would put the thermistor into the boiling water and once again measure the voltage from my divider resistor. This voltage corresponds to the temperature of boiling water, roughly 98 degrees C at my altitude. Next I would do the math to see how much the voltage has changed in the range of 0 degrees to 98 degrees C and from that I could get a good approximation of the temperature for all the voltages in between. you might check around as there might be a better data sheet available but you will still determine the voltage of a given temperature by the design of your voltage divider.

    John

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  • jw0752
    jw0752 over 10 years ago

    Hi Nicholas, You are right that wasn't a very good data sheet. It looked more like a sales flyer. Since it is a thermistor you will have to build it into some sort of a voltage divider and then read the voltage across one of the resistors in the divider circuit. The voltage that you get for a specific temperature will depend on the resistances that you choose to go into the divider. If I were doing it I would use an empirical approach and once I had the divider set up and I was reading the voltage I would put the thermistor in contact with melting ice and read my voltage. This voltage corresponds to 0 degrees C. Next I would calculate the temperature of boiling water for the atmospheric pressure where I live. Then I would put the thermistor into the boiling water and once again measure the voltage from my divider resistor. This voltage corresponds to the temperature of boiling water, roughly 98 degrees C at my altitude. Next I would do the math to see how much the voltage has changed in the range of 0 degrees to 98 degrees C and from that I could get a good approximation of the temperature for all the voltages in between. you might check around as there might be a better data sheet available but you will still determine the voltage of a given temperature by the design of your voltage divider.

    John

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  • Former Member
    Former Member over 10 years ago in reply to jw0752

    I figured this would be the case... I am using it with a Raspberry Pi and an ADC so I can read/write the voltages for desired temperatures (0C and 100C) and then solve for the line... Was hoping there might be a better solution than this lol.

     

    Thanks!

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  • Robert Peter Oakes
    Robert Peter Oakes over 10 years ago in reply to Former Member

    Not really, unless you adopt the RC Timer system mconners  posted a little while ago, that eliminated the ADC, use the thermistor instead of the Photoresistor

     

    find it here: http://www.element14.com/community/groups/stemacademy/blog/2014/12/23/reading-a-photo-sensor-with-the-raspberry-pi-b

     

    Regards

     

    peter

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