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Resistors in parallel

salesm21
salesm21 over 4 years ago

I know this seems simple, it probably is. But I keep getting told that the first two resistors in this circuit (namely the 10k and 15k resistors) are in parallel and I just don't see it. The def of a parallel resistor is one that is attached across another resistors in a way that the both have the same voltage drop. The 10k is going to get a different voltage than the 15k because the 10k is in series with the source. Any help would be great.

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  • michaelkellett
    0 michaelkellett over 4 years ago

    It's because a voltage source has an impedance or resistance of zero. So for impedance analysis you can set it to zero.

    Thevenin's theorem also states that you can replace a voltage source in series with a resistor with a current source in parallel with that resistance (or vice versa) - and everything works the same.

     

    There is a Wiki article (and lots of other stuff on the web Google Thevenin Theorem and Norton Theorem and Kirchoff for the full set of key linear circuit theorems).

     

    https://en.wikipedia.org/wiki/Th%C3%A9venin%27s_theorem

     

    But you are correct - the resitors are NOT in parallel, it is that the combination of voltage source and resistors can replaced by a single resistor (value = the two in parallel) and a voltage source (which will have a different voltage from the original source).

     

    I can't draw diagrams from here but there are lots on the web.

     

    MK

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