Hello Everyone,
Lately I have been trying to figure out how to calculate the current draw of circuits but I ran into a problem with battery charging circuits. My question is whether to plug in the battery to the circuit to obtain a correct reading?
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Hello Everyone,
Lately I have been trying to figure out how to calculate the current draw of circuits but I ran into a problem with battery charging circuits. My question is whether to plug in the battery to the circuit to obtain a correct reading?
I was wondering whether the battery made a difference when calculating the current, though my circuit has a voltage regulator that the output goes to the battery instead of the battery being in the initial circuit.
It depends where you are measuring the current.
If you measure current to the regulator, you can't tell how much is going into the circuit, how much is going into the battery and how much is coming from the battery. If you disconnect the battery, you can determine current to the circuit, but if the voltage changes when the battery is inserted, the current may also be different.
If you measure at the output of the regulator and battery, it will capture all current to the circuit, but will not indicate how much is being used to charge the battery nor how much is coming from either supply.
You may need to measure at more than one place to know everything.
I am using ohms law to calculate the current, so I am measuring the resistance across the input terminals so does the resulting calculation produce the maximum current draw from the circuit?
You never want to hook up the leads of your Ohmmeter to a power source.
An ideal voltmeter has infinite input impedance. Therefore, if you hook it up to a current source, you will cause it to provide infinite power.
An ideal ammeter has zero input impedance, therefore, it you hook across a voltage source, you will cause it to provide infinite power.
Current is measured through a point. Your current meter has a maximum safe value it can measure. If this is greater than the current you anticipate, go ahead and break the circuit and and insert your ammeter and charge the battery through it. This presumes your ammeter is bipolar, otherwise, mind the polarity.
For more permanent solution, get a shunt resistor and a panel meter.