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Ask an Expert Forum Monitoring of an event by external interrupt method. Here LCD is not working, can anyone help me please
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Monitoring of an event by external interrupt method. Here LCD is not working, can anyone help me please

Md_Enamul
Md_Enamul over 2 years ago

image

#include <mega32.h>

#include <alcd.h>

#include <stdlib.h>

#define output_ddr DDRB

#define output_port PORTB

char disp[16];

unsigned int i=0, k=0;

void display_lcd(void)

{

lcd_gotoxy(0,0);

itoa(i,disp);

lcd_puts(disp);

lcd_gotoxy(0,1);

itoa(k,disp);

lcd_puts(disp);

}

void main(void)

{

char move=0;

output_ddr=0xFF;

2output_port=0x80;

GICR=(1<<INT1) | (1<<INT0) | (0<<INT2);

MCUCR=(1<<ISC11) | (0<<ISC10) | (1<<ISC01) | (0<<ISC00);

lcd_init(16);

while (1)

{

if (GIFR & 0x80)

{

move=2;

GIFR = GIFR | 0x80;

}

if (GIFR & 0x40)

{

move=1;

GIFR = GIFR | 0x40;

}

display_lcd();

if (move==1)

{

output_port=output_port>>1;

if (output_port==0)

output_port=0x80;

}

if (move==2)

{

output_port=output_port<<1;

if (output_port==0)

output_port=0x01;

}

for (i=0; i<100; i++)

{

for (k=0; k<3000; k++)

{

// looping to create a delay

}

}

}

}

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  • shabaz
    shabaz over 2 years ago +2 verified
    Your code is not complete. Where are you specifying what GPIO pins are connected to the display? Also, are you running this for real, or in a simulation? If it is for real, then you probably need to…
  • shabaz
    +1 shabaz over 2 years ago

    Your code is not complete. Where are you specifying what GPIO pins are connected to the display?

    Also, are you running this for real, or in a simulation? If it is for real, then you probably need to change your circuit a bit.

    There must be hundreds of examples of this online that you could examine by the way. Google "atmega32 lcd proteus".

    (There's 54000 hits, surely one of those works).

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  • Md_Enamul
    0 Md_Enamul over 2 years ago in reply to shabaz

    I run it for real and simulation,for both LED is working but LCD is not. Thank you for the clarification

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