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Forum Driver Circuit for a Reciprocating Water Pump in a Medical Device
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Related

Driver Circuit for a Reciprocating Water Pump in a Medical Device

jw0752
jw0752 20 days ago

Hello Friends,

I am working on servicing a circuit board that is used in a Medical Dental sterilizer. The circuit boards used in this model of sterilizer seem to have a chronic problem with a circuit that drives a reciprocating water pump. Here is a schematic of the circuit that fails:

image

My question is what is the advantage to using this circuit configuaration to drive the pump? The gate of the N CH MOSFET turns on and pulls one leg of the load to the negative rail and also turns on the P CH MOSFET about 20 microseconds later pulling the other leg of the load up to the positive rail. While this seems to work quite well it seems to me to be an added complication to be switching both legs of the load. I am hoping for some insight into what the advantage might be in using this configuaration. The Rds (on) of the N CH is about 60 milli Ohm and the Rds of the P CH is about 13 milli Ohm. While I am not certain this is probably a Pulsed circuit as I suspect that the pump needs a Pulsed drive to properly function. My hope is that in better understanding the advantages of this circuit design I might be able to modify it to lower the present failure rate. Failure is usually a shorted P CH Mosfet, A Heat Destroyed N CH MOSFET and a Shorted D26 Diode.

Any insights you may have will be appreciated.

John

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  • michaelkellett
    michaelkellett 20 days ago in reply to jw0752 +2
    Well, the circuit looks a bit weird - I can only think that it has evolved. On similar things I have wanted to protect the load against the low side MOSFET failing short circuit and added a high side…
  • jw0752
    jw0752 19 days ago in reply to Jan Cumps +2
    Hi Jan, How have you been? I can't tell you how happy it makes me to see so many of the old gang still together.
  • Jan Cumps
    Jan Cumps 20 days ago +1
    Is it possible that the fragile gate of G17 sees too much high (inductive generated) voltage, from motor via R103 and R100, when the motor switches off? Maybe hang an isolated scope between drain and gate…
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  • jw0752
    0 jw0752 20 days ago

    Hi Michael,

    Just the man who may be able to help me. I thought the bit map would be able to be zoomed. Lets try it again.

    image

    Thanks John

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  • michaelkellett
    0 michaelkellett 20 days ago in reply to jw0752

    Well, the circuit looks a bit weird - I can only think that it has evolved.

    On similar things I have wanted to protect the load against the low side MOSFET failing short circuit and added a high side device controlled by a the system processor at low speed.

    This circuit looks as if it may have started like that and then someone decided that the low side MOSFET could operate the high side, but forgot that this would destroy the protective function of the high side MOSFET.

    There is a clue in that both R100 and R88 are pointless (unless there are connections to R88 you haven't shown.).

    image

     I made a model in LTSpice and it doesn't show anything bad.

    I could improve the model if you could tell me the operating voltage, the typical drive waveform on gate of Q15 and the resistance and inductance of the load. (Or failing that is the load a solenoid or a traditional motor.)

    MK

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  • jw0752
    0 jw0752 19 days ago in reply to michaelkellett

    Thanks for your insights. What you said makes sense. Since so far I have only seen the boards and what I know about the sterilizer is hearsay from field technicians. I have inquiries out to them about more details such as voltages. I am pretty sure that the pump is a spring loaded solenoid that  is workig with two check valves to produce the pumping action. In your simulation is there a reason why you didn't connect the anode of D1 to the Source of N CH MOSFET?

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  • michaelkellett
    0 michaelkellett 19 days ago in reply to jw0752

    I made a mistake in the connection of D1.

    This is a better simulation (with the right circuit, similar diodes to yours for D1 and D2, possibly better values for the load).

    image

    The currents in D1 and D2 are identical which is why you can only see I(D1).

    By adjusting the timing you can set the peak diode currents to Vsupply/Load R.

    D1 and D2 are rated at 1A, Q15 is a protected MOSFET and should be fine with 4A continuous current. Q17 can handle a lot more current.

    It looks as if the diodes are the weakest link but what they actually see depends on the timing, supply voltage and load parameters.

    LTspice is free - I can send the model if you would like it.

    MK

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  • jw0752
    0 jw0752 19 days ago in reply to michaelkellett

    Thanks Michael for taking the time to further investigate. I have the LT Spice program and I would welcome your model so I can play with it myself. 

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  • michaelkellett
    0 michaelkellett 19 days ago in reply to jw0752

    LTSpice file here:

    https://www.dropbox.com/scl/fo/876wu0j1vuus2e9t4yz0k/ABlNGiq6fHZOnWuOwdkZHkI?rlkey=9rs366j5r73tu3lft7f4a8rgg&dl=0

    MK

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  • michaelkellett
    0 michaelkellett 19 days ago in reply to jw0752

    LTSpice file here:

    https://www.dropbox.com/scl/fo/876wu0j1vuus2e9t4yz0k/ABlNGiq6fHZOnWuOwdkZHkI?rlkey=9rs366j5r73tu3lft7f4a8rgg&dl=0

    MK

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