Hi all,
I am just thinking about developing a circuit to charged a 12 Volt battery and the charging circuit will be porwered by a second battery
Hi all,
I am just thinking about developing a circuit to charged a 12 Volt battery and the charging circuit will be porwered by a second battery
Hello my name is Conroy and i am from Jamaica.. What if a inverter is being connected to a battery source to give out a AC energy of 120volts and you use back that 120AC energy to power a battery charger to charge back that same battery that needs to keep charge to keep the inverter going. Is that possible?
Hello my name is Conroy and i am from Jamaica.. What if a inverter is being connected to a battery source to give out a AC energy of 120volts and you use back that 120AC energy to power a battery charger to charge back that same battery that needs to keep charge to keep the inverter going. Is that possible?
It's perfectly possible, but quite useless.
All the energy from the battery will be lost warming up the inverter and the battery. When you charge a battery you always need to put more energy in than you took out to get it back to the original state. ALL inverters are less than 100% efficient.
There is no way to get energy for 'free' no matter how cleverly you connect up batteries or magnets.
MK
Think about this:
To charge a 12V battery at 10A you need 120W. If your inverter was 100% efficient, and all your wires had no resistance, you would need 120W back from the battery (10A).
If your inverter is only 95% efficient, you would need 126W (10.5A). So You are drawing 10.5A from the battery and only charging with 10A, your battery will soon be dead.
It gets more complicated when you take battery resistance into account. You can't just charge the battery at 12V, you need 14V or 15V to get current flowing into the battery.
At 15V @ 10A, you are using 150W, so it would draw 12.5A from the battery charger at 12V, your battery is dying even faster. Inside the inverter there are losses in the transformer, losses in the diodes and transistor junctions, and all the connecting wires have resistance, causing energy loss as heat.
Scott