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LM317 in parallel - Answered -> LM2596 circuit question

ckambiselis

Hello,

 

I am building a DC-DC converter to convert the 14.8v 6A power coming from a professional camera battery to 9V 2.5A used by a DSLR, I am trying to build this converter using the LM317 since it's the only easily available power regulator (which I don't have to order 2500pcs to place an order), the problem is the LM317 can only output 1.5A max, can I build the circuit using 2 of them and connecting the outputs of each circuit in paralel to get 9V 3A, is there going to be any kind of problem that may fry the camera?

 

Thank you

Oscar

 

Message was edited by: Christos Oscar Kambiselis

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    Hi all,

     

    I agree with all comments, better the LM2596 than a linear regulator, probably you would have loses about 15W with linear, so switched mode power supply will be better, because of the battery lifetime, and for the heatsink that would be needed.

     

    The module you show, looks great!! But in order to calculate the heatsink you need, we must know the efficientcy of this module, in order to know the power loses.

    Also as Sheldon says it seems to be heatsunk through the ground plane, furthermore if the manufacturer recommends heatsink, probably it will recommend how mount it, or which surface must be in touch with the heatsink.

    Do you have a link or the datasheet of the module? Even, you should know how much heat can the external box disipate?

    But, step by step, first we have to know the efficientcy and the loses, so a datasheet would be great.

     

    I hope I could help.

     

    Let us know how your project goes on.

     

    Regards,

    Miguel

Reply
  • 0

    Hi all,

     

    I agree with all comments, better the LM2596 than a linear regulator, probably you would have loses about 15W with linear, so switched mode power supply will be better, because of the battery lifetime, and for the heatsink that would be needed.

     

    The module you show, looks great!! But in order to calculate the heatsink you need, we must know the efficientcy of this module, in order to know the power loses.

    Also as Sheldon says it seems to be heatsunk through the ground plane, furthermore if the manufacturer recommends heatsink, probably it will recommend how mount it, or which surface must be in touch with the heatsink.

    Do you have a link or the datasheet of the module? Even, you should know how much heat can the external box disipate?

    But, step by step, first we have to know the efficientcy and the loses, so a datasheet would be great.

     

    I hope I could help.

     

    Let us know how your project goes on.

     

    Regards,

    Miguel

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