element14 Community
element14 Community
    Register Log In
  • Site
  • Search
  • Log In Register
  • About Us
  • Community Hub
    Community Hub
    • What's New on element14
    • Feedback and Support
    • Benefits of Membership
    • Personal Blogs
    • Members Area
    • Achievement Levels
  • Learn
    Learn
    • Ask an Expert
    • eBooks
    • element14 presents
    • Learning Center
    • Tech Spotlight
    • STEM Academy
    • Webinars, Training and Events
    • Learning Groups
  • Technologies
    Technologies
    • 3D Printing
    • FPGA
    • Industrial Automation
    • Internet of Things
    • Power & Energy
    • Sensors
    • Technology Groups
  • Challenges & Projects
    Challenges & Projects
    • Design Challenges
    • element14 presents Projects
    • Project14
    • Arduino Projects
    • Raspberry Pi Projects
    • Project Groups
  • Products
    Products
    • Arduino
    • Avnet Boards Community
    • Dev Tools
    • Manufacturers
    • Multicomp Pro
    • Product Groups
    • Raspberry Pi
    • RoadTests & Reviews
  • Store
    Store
    • Visit Your Store
    • Choose another store...
      • Europe
      •  Austria (German)
      •  Belgium (Dutch, French)
      •  Bulgaria (Bulgarian)
      •  Czech Republic (Czech)
      •  Denmark (Danish)
      •  Estonia (Estonian)
      •  Finland (Finnish)
      •  France (French)
      •  Germany (German)
      •  Hungary (Hungarian)
      •  Ireland
      •  Israel
      •  Italy (Italian)
      •  Latvia (Latvian)
      •  
      •  Lithuania (Lithuanian)
      •  Netherlands (Dutch)
      •  Norway (Norwegian)
      •  Poland (Polish)
      •  Portugal (Portuguese)
      •  Romania (Romanian)
      •  Russia (Russian)
      •  Slovakia (Slovak)
      •  Slovenia (Slovenian)
      •  Spain (Spanish)
      •  Sweden (Swedish)
      •  Switzerland(German, French)
      •  Turkey (Turkish)
      •  United Kingdom
      • Asia Pacific
      •  Australia
      •  China
      •  Hong Kong
      •  India
      •  Korea (Korean)
      •  Malaysia
      •  New Zealand
      •  Philippines
      •  Singapore
      •  Taiwan
      •  Thailand (Thai)
      • Americas
      •  Brazil (Portuguese)
      •  Canada
      •  Mexico (Spanish)
      •  United States
      Can't find the country/region you're looking for? Visit our export site or find a local distributor.
  • Translate
  • Profile
  • Settings
Essentials
  • Learn
  • Learning Center
  • Essentials
  • More
  • Cancel
Essentials
Forum Current question
  • Forum
  • Documents
  • Polls
  • Files
  • Members
  • Mentions
  • Sub-Groups
  • Tags
  • More
  • Cancel
  • New
Join Essentials to participate - click to join for free!
Actions
  • Share
  • More
  • Cancel
Forum Thread Details
  • Replies 4 replies
  • Subscribers 1019 subscribers
  • Views 1499 views
  • Users 0 members are here
Related

Current question

salesm21
salesm21 over 7 years ago

Attatched I have a photo of a small circuit I set up (I know its simple but I am just starting out) and realized something weird. When I put my test leads over my resistor I got very low resistance on my resistor which I thought would take the majority of the drop since the led offers little resistance. Also odd was when I turned my MM onto amps the DC power supplies current reading went up. Why is that? image

  • Sign in to reply
  • Cancel

Top Replies

  • michaelkellett
    michaelkellett over 7 years ago +3
    You've got a 3.2V voltage source (your PSU) driving a resistor and LED in series. The LED behaves like a diode with quite a high forward voltage drop. I found a nice cheap blue LED a bit like yours on…
  • jw0752
    jw0752 over 7 years ago +3
    Hi Mitchell, If you turned your meter to current measurement with the leads hooked across the resistor you would have put a short across the resistor effectively taking it out of the circuit. Since the…
  • salesm21
    salesm21 over 7 years ago in reply to jw0752 +1
    John, So as I understand it, if the meter wants to know current it creates a path of little resistance so that all the current is read through the meter. However how does this work in a parallel circuit…
  • michaelkellett
    michaelkellett over 7 years ago

    You've got a 3.2V voltage source (your PSU) driving a resistor and LED in series. The LED behaves like a diode with quite a high forward voltage drop.  I found a nice cheap blue LED a bit like yours on Farnell ( 2377467) - if you download the data sheet you'll see that they specify the forward voltage as 3.3V typical at 20mA. Diodes and LEDs are very non linear for for their forward voltage/current relationship but for your diode to drop about 2.7V at 3mA (which I can read on you psu) seems quite reasonable.

     

    Ohms law doesn't apply to diodes ! The current rises much more rapidly as the forward voltage increases than it does with a resistor.

     

    Here's a tutorial on LEDs (looks OK but their are many others):  https://www.electronics-tutorials.ws/diode/diode_8.html

     

    Hope this helps.

     

    MK

    • Cancel
    • Vote Up +3 Vote Down
    • Sign in to reply
    • Cancel
  • jw0752
    jw0752 over 7 years ago

    Hi Mitchell,

    If you turned your meter to current measurement with the leads hooked across the resistor you would have put a short across the resistor effectively taking it out of the circuit. Since the circuit would have less resistance the current would go up. The resistor is important in LED circuits as it acts like a limit so that the current of the LED can't go higher than the LED can tolerate.

    John

    • Cancel
    • Vote Up +3 Vote Down
    • Sign in to reply
    • Cancel
  • salesm21
    salesm21 over 7 years ago in reply to jw0752

    John,

    So as I understand it, if the meter wants to know current it creates a path of little resistance so that all the current is read through the meter. However how does this work in a parallel circuit? If my branch all of the sudden has 0 resistance all my current will drop across that branch and ill have none across the other branches. How do you effectively measure that?

    • Cancel
    • Vote Up +1 Vote Down
    • Sign in to reply
    • Cancel
  • jw0752
    jw0752 over 7 years ago in reply to salesm21

    When using the Ammeter properly it is always necessary to break the circuit and put the ammeter in series with the rest of the circuit. You are correct the Ammeter has a very low precision resistor across its leads and the meter reads the voltage drop across this resistor and displays the output as Amps or milliamps.

     

    John

    • Cancel
    • Vote Up 0 Vote Down
    • Sign in to reply
    • Cancel
element14 Community

element14 is the first online community specifically for engineers. Connect with your peers and get expert answers to your questions.

  • Members
  • Learn
  • Technologies
  • Challenges & Projects
  • Products
  • Store
  • About Us
  • Feedback & Support
  • FAQs
  • Terms of Use
  • Privacy Policy
  • Legal and Copyright Notices
  • Sitemap
  • Cookies

An Avnet Company © 2025 Premier Farnell Limited. All Rights Reserved.

Premier Farnell Ltd, registered in England and Wales (no 00876412), registered office: Farnell House, Forge Lane, Leeds LS12 2NE.

ICP 备案号 10220084.

Follow element14

  • X
  • Facebook
  • linkedin
  • YouTube