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Having sketch problems.

Former Member
Former Member over 10 years ago

I am having trouble with my sketch.  I am using an ultrasonic distance to activate relay.  Relay stays on all the time.

 

 

 

 

#define trigPin 12

#define echoPin 13

int relay2 = 2;

int i = 1000;

 

 

void setup() {

Serial.begin (9600);

pinMode(trigPin, OUTPUT);

pinMode(echoPin, INPUT);

pinMode(relay2, OUTPUT);

}

 

 

void loop() {

long duration, distance;

digitalWrite(trigPin, LOW);

delayMicroseconds(2);

digitalWrite(trigPin, HIGH);

delayMicroseconds(10);

digitalWrite(trigPin, LOW);

duration = pulseIn(echoPin, HIGH);

distance = (duration/2) / 29.1;

digitalWrite(2, LOW);

if (distance >= 25 || distance <= 2){

   Serial.println("Out of range");

}

if (i >= 4){

delay(i);

(distance >= 10);

(distance <= 8);

 

 

 

 

 

 

i = i/2;

}

  else {

   digitalWrite(2, HIGH);

   digitalWrite(2, LOW);

   Serial.print(distance);

   Serial.println(" in");

    delay(i);

  digitalWrite(2, LOW);

  delay(i);

digitalWrite(2, HIGH);

 

 

i = i/2;

}

delay(2000);

}

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  • Robert Peter Oakes
    0 Robert Peter Oakes over 10 years ago

    I dont understand why you have all the DigitalWrite(2, low) and (2,high) statements the way you do, the relay if it is mechanical will never responsd that quickly

     

    these two statements seem obsolete as they do nothing

    (distance >= 10);

    (distance <= 8);

     

    and your comparison to i starts out with i=1000 and will not execute the relay pulse untill i<=4 so that means i/2 +2000ms delay each time as I goes from 1000 to 3 so thats about

    (1000, 500, 250, 125, 62, 31, 16, 8, 4) 9*2000 = 20 or more seconds before the relay will do anything

     

    Then your delays get so small due to using i and never resetting it once it gets to almost zero from 1000 that the relay will apear to sit energised or not depending what a High value on the output does

     

    So now we know the issues, what is it you really want the code to so, use a flow chart or plain english description (Not Code)

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  • Former Member
    0 Former Member over 10 years ago in reply to Robert Peter Oakes

    peter,

    HEre is what I am trying to do.  The relay activates water pump .

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  • Former Member
    0 Former Member over 10 years ago in reply to Robert Peter Oakes

    peter,

    HEre is what I am trying to do.  The relay activates water pump .

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