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How to turn an led on and off via serial?

jreeve17

Im trying to use this code to turn LED's on and  off via serial. The only problem is that i can't get them to go off on their own, the only way to do it is by resetting tha arduino. Does anyone know how to change the code to turn them off via serial?

Or is there a better code that someone knows to use?

 

 

void setup(){

  Serial.begin(9600);

 

  pinMode(5, OUTPUT);

  pinMode(6, OUTPUT);

 

}

 

void loop (){

  if (Serial.available()) {

 

 

    char ser = Serial.read();

 

    switch (ser) {

 

      case '3':

        triggerPin(5);

        break;

      case '4':

        triggerPin(6);

        break;

 

    }

  }

}

 

void triggerPin(int pin){

  digitalWrite(pin, HIGH);

}

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  • 0

    Hello,

    if you manage to only get it working by serial here is a working sketch you could use for example.

    Just change it the way you want it to really do the jobs.

     

     

    boolean statePin5 = LOW; // To store the state of the pin 5

    boolean statePin6 = LOW; // same thing for pin 6

     

    void setup(){

      Serial.begin(9600);

     

      pinMode(5, OUTPUT);

      pinMode(6, OUTPUT);

    }

     

    void loop (){

      if (Serial.available()) {

       

        char ser = Serial.read();

     

        switch (ser) {

     

          case '3':

            statePin5 = !statePin5; // change the state of the pin 5

            triggerPin(5, statePin5);

            break;

          case '4':

            statePin6 = !statePin6; // change the state of the pin 6

            triggerPin(6, statePin6);

            break;

          default:  // in case you have something different coming through serial

            digitalWrite(5, LOW); // back to low

            digitalWrite(6, LOW); // back to low

            statePin5 = !statePin5; // don't forget to change the state of each pin

            statePin6 = !statePin6; // also or you'll be missing a state in the sequence

            break;

        }

      }

    }

     

    void triggerPin(int pin, int statePin){ // adding the pin state

      digitalWrite(pin, statePin); // enjoy !!!

    }

     

     

    In case you really want to use the switch/case function don't forget to use the "default" case that is really powerfull to save a lot of trouble.

     

    Hope you'll find your way.

    Good luck.

Reply
  • 0

    Hello,

    if you manage to only get it working by serial here is a working sketch you could use for example.

    Just change it the way you want it to really do the jobs.

     

     

    boolean statePin5 = LOW; // To store the state of the pin 5

    boolean statePin6 = LOW; // same thing for pin 6

     

    void setup(){

      Serial.begin(9600);

     

      pinMode(5, OUTPUT);

      pinMode(6, OUTPUT);

    }

     

    void loop (){

      if (Serial.available()) {

       

        char ser = Serial.read();

     

        switch (ser) {

     

          case '3':

            statePin5 = !statePin5; // change the state of the pin 5

            triggerPin(5, statePin5);

            break;

          case '4':

            statePin6 = !statePin6; // change the state of the pin 6

            triggerPin(6, statePin6);

            break;

          default:  // in case you have something different coming through serial

            digitalWrite(5, LOW); // back to low

            digitalWrite(6, LOW); // back to low

            statePin5 = !statePin5; // don't forget to change the state of each pin

            statePin6 = !statePin6; // also or you'll be missing a state in the sequence

            break;

        }

      }

    }

     

    void triggerPin(int pin, int statePin){ // adding the pin state

      digitalWrite(pin, statePin); // enjoy !!!

    }

     

     

    In case you really want to use the switch/case function don't forget to use the "default" case that is really powerfull to save a lot of trouble.

     

    Hope you'll find your way.

    Good luck.

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