rebel LED package

Chuck Huber wrote:

M.Klaassens wrote:

Hi,

 

I designed the footprint, as attached. But now I want to connect all

via's to the V(ia)-pin. Anyone any suggestions?

 

I ran across this problem with a PCB mounted fuse clip designed to

accept one end of a cylindrical fuse.  The clip has two pins on the

same net.

...

Another way to deal with this situation is to simply put multiple pins in

the schematic Symbol, each pin being connected to one pad in the Device.  In

the schematic you simply connect your Net to both pins.  This produces

exactly what you want without any additional copper layers not checked by

DRC, and without any DRC errors.

--

Bert Menkveld

At present, there is no way to connect multiple plated through-holes

to the same pin in the schematic - it's always a one-to-one

relationship between pads/holes in the package and pins in the

schematic.

To work around this, I created the part with some copper on the bFill

(layer 101) layer and included that layer with the top copper in the

.cam file.  This avoids all the DRC errors produced when you have

bottom copper bridging both pins.

 

In my application, I have a 70 to 90 amp impulse lasting about 2.5 to

3.0 us going through the part.  I wanted to make sure that all the

holes were connected to copper to reduce inductive and IR impedence

losses. Basically, the current traveling along the trace had to turn

"up" to get to the clip.  This amounts to a 1/4 turn inductor.

 

 

In the case of the Rebel LED package, you may want add a polygon on

the tFill (101) and bFill (102) layers that surrounds all the vias. Be

sure to modify you CAM file to include tFill with the top copper

and bFill with bottom copper.  On the schematic, you can have one pin

connected to one of the vias.

 

When you produce the gerber files, double check the top and bottom

copper layers to make sure the fill has been included.

 

While it's not the ideal approach, it is a decent workaround that will

get you copper where you need it.

 

Hope this helps,

 

    - Chuck

Chuck Huber wrote:

M.Klaassens wrote:

Hi,

 

I designed the footprint, as attached. But now I want to connect all

via's to the V(ia)-pin. Anyone any suggestions?

 

I ran across this problem with a PCB mounted fuse clip designed to

accept one end of a cylindrical fuse.  The clip has two pins on the

same net.

...

Another way to deal with this situation is to simply put multiple pins in

the schematic Symbol, each pin being connected to one pad in the Device.  In

the schematic you simply connect your Net to both pins.  This produces

exactly what you want without any additional copper layers not checked by

DRC, and without any DRC errors.

--

Bert Menkveld

At present, there is no way to connect multiple plated through-holes

to the same pin in the schematic - it's always a one-to-one

relationship between pads/holes in the package and pins in the

schematic.

To work around this, I created the part with some copper on the bFill

(layer 101) layer and included that layer with the top copper in the

.cam file.  This avoids all the DRC errors produced when you have

bottom copper bridging both pins.

 

In my application, I have a 70 to 90 amp impulse lasting about 2.5 to

3.0 us going through the part.  I wanted to make sure that all the

holes were connected to copper to reduce inductive and IR impedence

losses. Basically, the current traveling along the trace had to turn

"up" to get to the clip.  This amounts to a 1/4 turn inductor.

 

 

In the case of the Rebel LED package, you may want add a polygon on

the tFill (101) and bFill (102) layers that surrounds all the vias. Be

sure to modify you CAM file to include tFill with the top copper

and bFill with bottom copper.  On the schematic, you can have one pin

connected to one of the vias.

 

When you produce the gerber files, double check the top and bottom

copper layers to make sure the fill has been included.

 

While it's not the ideal approach, it is a decent workaround that will

get you copper where you need it.

 

Hope this helps,

 

    - Chuck