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Forum multiple pre increment/post increment in expression of C language
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Related

multiple pre increment/post increment in expression of C language

dr.akshay_1980@yahoo.com
dr.akshay_1980@yahoo.com over 9 years ago

I would like to know the explanation for the following expression evaluation in C under windows TURBO c..

void main()

{

     int i=4;

    int x;

    x= ++i + ++i + ++i;   // i becomes 5 then 6 added becomes 11 and then incremented to 12 so 11+12=23   

    printf("%d",x);

    getch();

}

when the above was executed value of x comes out to be 21

 

Slightly eliminating the x variable in the above

 

void main()

{

    int i=4;

    printf("%d", ++i + ++i + ++i);   //accordingly at this step  5+6+7=18

    getch();

}

when the above is executed the answer comes out to be 18


Can anyone provide a decent explanation step by step and why two answers are different???


Thanks in advance.

Akshay


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  • michaelkellett
    michaelkellett over 9 years ago in reply to dr.akshay_1980@yahoo.com +3
    If anyone asked you that (kind of) question at an interview (unless, perhaps, the job was to revise the C standard specification) you should explain that the only reasonable approach to such code was to…
  • gadget.iom
    gadget.iom over 9 years ago in reply to dr.akshay_1980@yahoo.com +2
    Ahhh... Complete code usually helps As for the problem... You have fallen victim to undefined behaviour as a result of each compilers interpretation of ambiguous code.
  • shabaz
    shabaz over 9 years ago in reply to dr.akshay_1980@yahoo.com +1
    Oh. I now get this is purely an academic question (and a very esoteric one not in my area of interest, sorry!) In real life people wouldn't write that code.. perhaps it is tested nowadays and therefore…
  • james.flynn
    0 james.flynn over 6 years ago in reply to phoenixcomm

    >James, you are on the right track and a good try.. And you actually ran the silliness. BUT to no avail, you did not understand the error message.

     

    Actually, I do understand the message and it is a WARNING not an ERROR.  In fact, when you take this program and run it, the result is: 19.  It didn't crash and burn or go puff. It didn't complain about 'i' as undefined or anything like that, in fact, it acted just like the warning it is.  Now I'm not saying this is good programming practice or anything like that because it isn't. I don't basically disagree with what you are saying, I'm just pointing out that it isn't an error in the language spec.  In fact, if you compile the code, you get a warning, but it does generate code (this is for an ARM Cortex-A7) that then executes:

    {
    int i=4;
    44: e3a03004 mov   r3, #4
    48: e58d3004 str   r3, [sp, #4]
    int x= ++i + ++i + ++i;  
    4c: e59d3004 ldr   r3, [sp, #4]
    50: e2833001 add   r3, r3, #1
    54: e58d3004 str   r3, [sp, #4]
    58: e59d3004 ldr   r3, [sp, #4]
    5c: e2833001 add   r3, r3, #1
    60: e58d3004 str   r3, [sp, #4]
    64: e59d2004 ldr   r2, [sp, #4]
    68: e59d3004 ldr   r3, [sp, #4]
    6c: e0822003 add   r2, r2, r3
    70: e59d3004 ldr   r3, [sp, #4]
    74: e2833001 add   r3, r3, #1
    78: e58d3004 str   r3, [sp, #4]
    7c: e59d3004 ldr   r3, [sp, #4]
    80: e0823003 add   r3, r2, r3
    84: e58d3000 str   r3, [sp]
    printf("x(%d) = ++i + ++i + ++i;\n",x);
    88: e59d1000 ldr   r1, [sp]
    8c: e3000000 movw  r0, #0
    90: e3400000 movt  r0, #0
    94: ebfffffe bl    0 <printf>
    }

     

    When you run this code, the result is 'x=19'.  So the code isn't 'uncompilable' because I just compiled it, it ran and produced an output.  That may not be the result you wanted or thought it should be because of the semantics associated with the sequence point rules in C and C++, but the assertion that the BNF supports your conclusion that it will not compile and result in an error is incorrect.  Different compilers all utilize different parsers in their construction--LALR, LL, SLR, GLR--and each will parse this statement differently; some may and some may-not compile the code due to the compiler writers interpretation, but I avoid blanket absolute statements.

     

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  • phoenixcomm
    0 phoenixcomm over 6 years ago in reply to james.flynn

    You are correct about different parsers. But I do believe better than 70% will fail.  Even though BNF allows it  Your parser won't. I don't know why folks keep bringing this thing out of its grave. Its like a zombie it just never dies.

    Oh BTW about obfuscated code. it like APL unreadable. that is  why I hate Python it like Fortran but with out line numbers.

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  • michaelkellett
    0 michaelkellett over 6 years ago in reply to james.flynn

    james.flynn  wrote:

     

    you can step through the statement using the 'C Operator Precedence' rules and determine the answer a compliant compiler would generate yourself. 

    This really isn't right.

    A compliant compiler is one which is compliant with a specified standard.

    ISO/IEC 9899 ("C99"|) and as far as I know all subsequent ISO C standards specify things like:

    i = ++i + 1;

    a[i++] = i;

     

    as undefined.

     

    This means that a compiler may make any result it likes and still be compliant.

    MK

     

     

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  • phoenixcomm
    0 phoenixcomm over 6 years ago in reply to michaelkellett

    No, not really if your code is not compliant. 1 it probably not run. I know folk love to talk about it but. And even if it does run there is no guaranty the answer will be correct.

    BTW the two examples you show maybe compliant. As in the first one if i started as 1 answer should be 3

    in #2 you increment i after the store OK. but things like

    i = i++ + i++ are illegal and not compliant as most if not all parsers (2 or 3 pass optimizing) will get very confused. (this is where we all got on this stupid train, and as for me its time to get off and do something more important.) 

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  • james.flynn
    0 james.flynn over 6 years ago in reply to phoenixcomm

    At this point the discussion really is a dead horse.  I compiled the code with GCC v5.x--which is a Compliant compiler (https://gcc.gnu.org/onlinedocs/gcc/Standards.html )--so your assertion that is it illegal and not compliant is flat out wrong.

     

    Rather than beating the horse, what I really want to highlight that people come to web-sites like element14 for primarily 2 reasons: (1) to get an answer to a question [I doubt they are going to come here to determine if their compiler is compliant] and (2) to find solutions to problems.  I responded to this thread because it is promulgating incorrect information about the compliance/legality of a correctly (though idiotic) C expression, then attempted to validate that information by incorrectly citing BNF notation.  The entire premises of the argument is invalidated by simply compiling the code segment and seeing that it does compile (though with a warning) and run.

     

    IMO, it is wrong to disseminate incorrect information as fact when it is really opinion.  

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