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Ask an Expert Forum Why is D5 failing?
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Why is D5 failing?

inavitech
inavitech over 1 year ago

image

Project I am working on. I'm not a board designer. Box integration is more my thing. This circuit is needed for providing a 13VDC output. Input power is 28VDC. When 28VDC is applied the power supply voltmeter drops to 6VDC, and it goes into current limiting mode. Current output is maxed out at 5 amps. D5 starts to look like a well done hotdog on the grill and begins to smoke. There were other parts of this circuit in the original design that are not being utilized, but as I said I'm not a board guy. I think with the removal of the unnecessary portion, the current is too high, thus R15's value is too low now. Figured maybe one of you on the forum might have the answer. So how this works is the tester utilizes 28VDC to test a battery pack. All of the other functions work properly when removing this part of the circuit from the equation. There is a test for a particular circuit in the battery that requires 13VDC to verify proper operation, so I can't ditch this portion of the tester. Maybe there is a better way to do this?

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  • inavitech
    inavitech over 1 year ago +4
    Well, I have it figured out. It is Q1. I looked at the spec sheet again and looked at it's installation on the prototyping board and the collector and base are swapped. So that is probably why the current…
  • dougw
    dougw over 1 year ago +3
    Was this circuit ever working, or was it just assembled and never worked? The connections for U1 don't make sense, but are not likely the problem. If the collector and emitter of Q1 are reversed, The…
  • JWx
    JWx over 1 year ago +1
    could Q1 be damaged (C-B shorted for example)?
  • dang74
    0 dang74 over 1 year ago

    I would have thought that U1 would have been involved in some kind of feed back function.  As it stands it's a unity buffer to nowhere.

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  • wolfgangfriedrich
    0 wolfgangfriedrich over 1 year ago in reply to dang74

    Agreed. The output probably should be connected to the base of the Darlington Q1. Same voltage level with more drive. 

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  • inavitech
    0 inavitech over 1 year ago in reply to dang74

    The circuit was redrawn from the original, minus a circuit path that was tied between D7, R15 and Q1 going to a shunt and automatic timing circuit with voltage monitor.

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  • JWx
    0 JWx over 1 year ago

    could Q1 be damaged (C-B shorted for example)? 

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  • dang74
    0 dang74 over 1 year ago

    To correct it break the connection between the noninverting input of U1 and the base of Q1.  Also break the connection between the output and inverting input of U1.  Connect the inverting input to your +13V using a resistor.  Connect the output of the opamp to the base of Q1 using a resistor.  Now it's time for a disclaimer, I am not sure if Q1 is a Darlington NPN or an SCR.  Either way, it might be necessary to also have an intermediary NPN to invert the signal to enable the negative feedback to work properly.

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  • inavitech
    0 inavitech over 1 year ago in reply to JWx

    Not sure. Will have to test it.

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  • dang74
    0 dang74 over 1 year ago

    Also wondering, have you verified that R15 is really 2k and not something like 2 OHM.

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  • inavitech
    0 inavitech over 1 year ago in reply to dang74

    Q1 is a Darlington NPN according to the spec sheet.

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  • inavitech
    0 inavitech over 1 year ago in reply to dang74

    It is 2K

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  • inavitech
    0 inavitech over 1 year ago in reply to inavitech

    Do I even need U1? I was wondering what its purpose was. All I did was redraw the circuit and omit the side with the voltage monitor, shunt and automatic timing system. Just using an old fashion stop watch as a timer and set up have the circuit wired to allow a multi-meter to be inserted or removed from the charge circuit via a switch.

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