this is a 2-phase stepper motor drive by a chinese company called SCKJMOTOR with the model number SC2680MH
it can be found here in this link http://sckjmotor.com/prodetail.asp?cid=3&scid=6&id=67
i am not much experienced with electronics so i cant figure out how to use it with out an instruction manual and sadly the manual is in chinese
so i thought maybe i can find some help here on element 14
you can see in the pictures the driver has lots off ports on it they go like + , PU, + , DR, + , MF, + , TM, +V, -V, +A, -A, +B, -B
here i think the " + " ports might be a 5V input so i guess i must give 5V in them, but why are there so many???? why do i need to give the driver 5V at 4 different ports ???
the port " PU " might be pules, i am just guessing, it might be to control the speed of the motor
the port " DR " maybe direction like forward-reverse, another guess
the port " MF " i have no idea, cant even guess this one
the ports " +V " and " -V" the driver says on the side " DC24-80V " so i guess i might have to give it some thing between 24V to 80V
the posts +A, -A, +B, -B are clear i guess, i just have to find the right coil pairs of the stepper motor and connect it to these ports
there is also some thing called a division setting table and it gives me values 1, 2, 4, 8, 16, 32, 64 and 128 , i think this must be some thing related to the step divisions of the stepper motor, need some help with that as well
please try to help me out with this, i am just starting to take interset in electronice and dont have any experience in this at all, just have some basic electronic knowledge since i am doing engineering and its my 1st year
thank you