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need help with a stepper driver

Former Member

imageimageimageimageimageimage

this is a 2-phase stepper motor drive by a chinese company called SCKJMOTOR with the model number SC2680MH

it can be found here in this link http://sckjmotor.com/prodetail.asp?cid=3&scid=6&id=67

i am not much experienced with electronics so i cant figure out how to use it with out an instruction manual and sadly the manual is in chinese image

so i thought maybe i can find some help here on element 14

 

you can see in the pictures  the driver has lots off ports on it they go like  + , PU, + , DR, + , MF, + ,  TM, +V, -V, +A, -A, +B, -B

 

here i think the " + " ports might be a 5V input so i guess i must give 5V in them, but why are there so many???? why do i need to give the driver 5V at 4 different ports ???   image

 

the port " PU " might be pules, i am just guessing, it might be to control the speed of the motor  

 

the port " DR " maybe direction like forward-reverse, another guess 

 

the port " MF " i have no idea, cant even guess this one   image

 

the ports " +V " and " -V" the driver says on the side " DC24-80V "  so i guess i might have to give it some thing between 24V to 80V

 

the posts  +A, -A, +B, -B  are clear i guess, i just have to find the right coil pairs of the stepper motor and connect it to these ports  image 

 

there is also some thing called a division setting table and it gives me values  1, 2, 4, 8, 16, 32, 64 and 128 , i think this must be some thing related to the step divisions of the stepper motor, need some help with that as well

 

please try to help me out with this, i am just starting to take interset in electronice and dont have any experience in this at all, just have some basic electronic knowledge since i am doing engineering and its my 1st year

 

thank you

  • 0 in reply to bodgy

    OK, I have spoken to the Chinese gentleman at work, unfortunately his English is not brilliant, but I think the gist of what he said is -

     

    1. The datasheet is poorly written.

     

    2. If D2 is OFF,  step pulse signal is enabled.

     

    3. If D2 is ON direction control is enabled  - if it is low (0->0.5v direction is one way), if it is high (4-5v) the direction is the other.

     

    The pulse width on the DR must be 2.5uS wide.

     

    The input impedance of the DR line in the controller is 220 Ohms.

     

    So, my guess is that with D2 off, you cannot reverse the motor direction, it is clockwise only, D2 ON, allows motor direction change via the DR line.

     

    The 24-80v is the supply for your motor.

     

    The datasheet mentions the zero point but I'm told gives no further information other than the TM relates to it..

     

     

    Colin

  • 0 in reply to bodgy

    i connected this motor to driver 

    image

     

    its a 6 wire stepper motor i found the +A -A +B -B wires and connected it to the driver in those ports 

     

    connected 24V to +V and -V

     

    first ran the motor in test mode which is D1 on, it runs fine when i keep the division table to 8 or higher ( as you can see in the driver pictures ) that is D6 off D5 off D4 on

     

    division table set to 8 the motor runs the fastest and runs slower as i go higher that is 16 32 64 128

     

    what is this division setting exactly  ???

     

     

    then i programed an arduino to give an pulse of width 1uS connected it to port PU and gave 5V in the first + port fron the top, it dint run then i gave 5V in the 2nd + port, the motor still does not run, i connected 5V to DR as well then the motor started running  but was very slow ( 1 rev in 6 secs) when the division setting is set to 8

    then i set the division setting to 1 that is D4 on D5 on D6 on , then the motor runs some what fast  ( 5 rotations in 1 sec ) ( D2 is on )

  • 0 in reply to Former Member

    Hello,

     

    A stepper motor have has his name said a step. Generally  one step turn the rotor about 1.8° so to do a entire turn you have to send 200 pulse to PU.

    If you put a division, you reduce the angle. so divide by 2 one step will turn the rotor by 0.9° so you have to send 400 pulse to PU to do one rotation.

    What is the frequency of your pulse, you said a width of 1us but not the frequency.

     

    Syncerely

    Man Long

  • 0 in reply to manlong

    hi,

     

    i am not sure about the frequency, what i am doing is, i connected the arduino to give the pulse and loaded the program of the blinking LED and changed the delay to 1uS between  the on and off signal

  • 0 in reply to Former Member

    If you see the blinking led that the frequency is too low. You have to increase the frequency.

    If for example the frequency is 10Hz, the LED blink every 0.1s, to do 200 pulses you have to wait about 20 seconds. And this without division.

    So you have to increase your pulse frequency, the number of pulse within 1 second to rotate your motor fastly.

    The speed of the motor is the same as the speed you send your pulse.

    More you use division (1,2,4,8,...) more you will be precise but you have to send 1,2,4 times more to do 1 rotation

     

    Man Long

  • 0 in reply to manlong

    i just realized a small mistake i was making in arduino program *facepalm* that i was taking to be microseconds was millisecond i was giving an on/off signal by the arduino with 1 millisecond delay in between [ delay(1) ], so i found an other command used for making delays in microsecond [ delayMicroseconds(500) ] so i changed the program a little and noticed that the max i can reduce it was 500 Microseconds

    now the on/off signal is with the delay of 500 Microseconds [ 1 sec = 100000 micro sec ]

     

    so now the motor is running almost 3 times faster  both forward and reverse

     

    one more thing, i have not made the arduinos and the drivers ground common, i have not used arduinos ground at all i have only taken the pulse from arduino and DR (direction) signal