Inductive charger

A coil in the charging base (always plugged in and on) couples to a mating coil in the hand unit to form a step down transformer. The transistor, Q1, is used as an oscillator at about 60 kHz which results in much more efficient energy transfer via the air core coupling than if the system were run at 60 Hz. The amplitude of the oscillations varies with the full wave rectifier 120 Hz unfiltered DC power but the frequency is relatively constant.

     E1           CR2          R1                                E3
  AC o----+----+--|>|-----+---/\/\---+----+----------------+-------+  Coupling
          |   ~|  CR1     |+   1K    |    |                |        ) Coil
        +-+-+  +--|<|--+  |          |    / R2             |        ) 200T
    RU1 |MOV|     CR3  |  |      C1 _|_   \ 390K           |        ) #30
        +-+-+  +--|>|--|--+   .01uF ---   /          CR5   |     E4 ) 1-1/2"
       E2 |    |  CR4  |       250V  |    \ MPSA +---|<|---|----+--+   
  AC o----+----+--|<|--+             |    |   44 |         |    |
              ~        |-     R3     |    | Q1 |/ C    C3 _|_  _|_ C2
                       +-----/\/\----+----+----|     .1uF ---  --- .0033uF
      CR1-CR4: 1N4005  |     15K               |\ E  250V  |    |  250V
                       |                R4       |         |    |
                       +---------------/\/\------+---------+----+
                                        1K

For the toothbrush, a 4 position switch selects between Off, Low, Medium, and High (S1B) and another set of contacts (S1A) also is activated by the same slide mechanism. The motor is a medium size permanent magnet type with carbon brushes.

                                       S1B
                              S1A  +--o->o
                 D1           _|_  |       R1,15,2W
             +---|>|---+------o o--+   L o---/\/\---+
    Coupling |         |                   R2,10,2W |
       Coil  +        _|_ BT1          M o---/\/\---+
       120T (          _  2.4V                      |
        #30 (         ___ .5A-h        H o----------+
     13/16"  +         _                            |
             |         |        +-------+           |
             +---------+--------| Motor |-----------+
                                +-------+

Hi Enrico!

Thank you for your input!

Yes, I did also find this example. :-)

I have now started with the design. I will try to feed the charger with 24VDC so I can use an "off-the shelf" walladapter to supply the charger. It's also easier to work with and build up prototypes and measure on.

I have added a 40 kHz oscillator since the inductor I have chosen is optimized for 40 kHz. I also think this is a nice frequency to work with since it will not cause too much trubbel with EMC and approval.

Once I have a good "transmitter" I think the receiver will not be too difficult to build. In the end of the day the complete design might turn out to not be very complicated at all.

It would be very nice to have a detection circuit as you suggest, but I guess that have to wiat until step 2. The primary goal is to proof that we can build an resonable effective inductive charger. When it works fine we might move on to step two which can be a detection circuit. I think the detection circuit can be done in different ways. CHange of inductance is one way. Simple radio transmitting is an other way. Light (infrared) indication is also an alternative.

I guess not having a detection circuit at all can also be an alternative.

Hi Enrico!

Thank you for your input!

Yes, I did also find this example. :-)

I have now started with the design. I will try to feed the charger with 24VDC so I can use an "off-the shelf" walladapter to supply the charger. It's also easier to work with and build up prototypes and measure on.

I have added a 40 kHz oscillator since the inductor I have chosen is optimized for 40 kHz. I also think this is a nice frequency to work with since it will not cause too much trubbel with EMC and approval.

Once I have a good "transmitter" I think the receiver will not be too difficult to build. In the end of the day the complete design might turn out to not be very complicated at all.

It would be very nice to have a detection circuit as you suggest, but I guess that have to wiat until step 2. The primary goal is to proof that we can build an resonable effective inductive charger. When it works fine we might move on to step two which can be a detection circuit. I think the detection circuit can be done in different ways. CHange of inductance is one way. Simple radio transmitting is an other way. Light (infrared) indication is also an alternative.

I guess not having a detection circuit at all can also be an alternative.

Hi Roger,

Be carefull building circuits with free running oscillators, these devices are known to overheat in low load condictions. This is also the case when the inductance of the primary coil drops (receiver removed). The switching frequency rises to such high values that the switching losses can overheat the switching devices. I think a better approach is using a dedicated quasi resonant flyback controller (such as On semiconducter NCP1207). This controller limits the maximum switching frequency and has additional benefits. Additional to your primary winding should be a second winding which acts as a demagnetization detection and supply voltage. This winding is also in the transmitter part. In your case (as a feedback circuit to monitor the output voltage is missing), this winding tells you what voltage is on the secondary winding (ratio aux /sec winding). An even bigger advantage is that these devices have a high voltage current source (to startup from the mains supply voltage) and switch off  when the voltage on the VCC pin reaches a certain value. In your case the voltage on the VCC pin can only reach a steady value if the receiver is attached and therefore you have a detection circuit (receiver attached or not). There are still a few difficulties. Due to the bad coupling betrween primary and secondary winding the voltage on the output is not exactly similar to the ratio between aux/sec. Also the drop in inductance (receiver gone) is tricky, however the maximum current trough the winding is limited by the controller (there is a primary peak current detection on the controller). Look at the datasheet, there are also application examples.

Best regards,

Enrico Migchels

Power Conversion Design Engineer

Heliox B.V.

Best - The Netherlands

www.heliox.nl

Hi Enrico!

You are very helpful. Thanks a lot!

I have done some calculations today and to me it doesn't look very good. If you have time maybe you can check if there is a major error in my calculations.

The reaktans in an inductor is: 2 x pi(3.14) x frequency x L (in henry)

With frequency of 40 kHz and a coil of 1000uH this gives 251.1 Ohm

If I connect to mains (230VAC) and rectify I will get approx 330VDC.

330V / 251 Ohm gives a current of 1.31A

The energy in an inductor is calculated with formula: W=L x 0.5 x I x I

In my example it gives 1000uH x 0.5 x 1.31 x 1.31 = 0.86mW

Assuming that I have no losses when transfer energy from one inductor to the second one it would mean that I one the receiver side also have 0.86 W. I'm looking for 6V on the second side, and with those figures I will only get 0.14 mA at 6V.

I need approx 1000 times more power still assuming that I have no losses.

Hmmm, I realize that calculating inductors is not my strong side. I will go back and check with my old schoolbooks because this can't be right.

Hi there Roger,

Luckely for you your situation isn't that bad. The output power for a flyback converter is given by the following formula:

Pout=0.5 x Ip^2 x Lp x fs

Ip = primary peakcurrent set by sense-resistor in source of FET, Ip= 1V/Rsense, 1V is the level given by the controller datasheet).

Lp is the primary inductace of your flyback transformer,

fs = switching frequency.

For the input power (pushed into the core) you should calculate with a factor Pout/0.85 (85% efficiency assumed).

For the following example: Ip = 3A and Fs, min = 40kHz, Lp = 500uH, your output power is 90W.

Note that increasing the peak current increases the output power fast, but take care that the ferrite core can not be exited more than 300mT, otherwise you will saturate the ferrite.

Best regards,

Enrico Migchels

Power Supply Design Engineer

Best - The Netherlands

www.heliox.nl