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Inductive charger

Former Member
Former Member over 15 years ago

I'm going to design an inductive charger and I have a lot of open questions and don't really where to start. I know about the principle how it works. I need help with several things.

The idea is to get 5-7VDC out oin the secondary side, and something like 100mA would be nice.

 

First of all, what switching frequency is suitable concerning size and efficency of components, and also regarding type approval issues? I think electrical toothbrushes uses approx. 60 kHz so maybe that is a suitable frequency.

Secondly, does anyone know about a design example I can use for a start?

Does anyone have any suggestions for suitable inductors? Supplier, part number etc?

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  • enrico.migchels
    0 enrico.migchels over 15 years ago

    Hi there Roger,

     

    It seems that you are trying to re-invent the wheel :-) SMPS chargers (3-5W) are readily available on the market for just a few dollars. However if the task is related to 'having fun' this is something else. However if you don't have expierence in switch mode power supplies this task is not easy. Remember also that you are dealing with a device which has a safety function. (a user must be able to touch the output voltage safely). You as designer are responisible for this safety function. Given all this, your circuit should be a flyback converter. Getting a suitable (and safe) transformer is difficult, other components are easy to get.

     

    A switching frequency of 60kHz is not uncommon. Your power switch is a MOSFET and the controller is a small 8pin device from a supplier such as ST, ON, etc. If you look at the datasheet of such a controller (UC3842B is old but a generic part) you will find a typical application. You can downscale it for your needs.

     

    If you have specific questions i might be able to help you.

     

    Best regards and lot's of luck

     

    Enrico Migchels

    Power Conversion Design Engineer

    Heliox. B.V.

    Best, The Netherlands

    www.heliox.nl

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  • Former Member
    0 Former Member over 15 years ago in reply to enrico.migchels

    Hi Enrico!

     

    Thank you for your answer.

     

    I'm sorry, but I was maybe clera enough with my question:

     

    I have a lot of experience with power supply designs in general with for examples DC/DC converts with all kind of topologies.

    What I want to do now is something that is similar to an inductive charger for an electrical toothbrush, menaing with one part that act as a "transmitter" but that are completly sealed and not possible to touch any electrical parts.

    The second part shall act as a "receiver" (toothbrush) and is also completly sealed.

     

    So, I will have two parts that is away from each other during normal use, and only close to each other when the battery shall be charged.

    To get a high efficency the physical design of those parts must be optimized so the inductors are placed very close to each other, and probably also a core need to be used. I think it's therefore not possible to use any "off-the shelf" products, but I might be wrong.

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  • SteveH
    0 SteveH over 15 years ago

    These can be quite simple and use 60 Hz - Just think of it as a transformer with really bad coupling or high leakage inductance. It may not be the most efficient, but for the kind of application it does not really matter much. My toothbrush uses just this simple of an approach. A 60 Hz, poorly coupled transformer to charge the batteries in 24 hours.

     

    Also see,

     

    http://en.wikipedia.org/wiki/Inductive_charging

     

    HTH - Steve H.

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  • enrico.migchels
    0 enrico.migchels over 15 years ago in reply to Former Member

    Hi Roger,

     

    Ok, it's clear. The design problem is not as big as you think. Just see the distance between transmitter (primary part of your flyback converter) and receiver (secondary part of flyback converter) as the air gap which is normally in the centerleg of the core construction. In your situation the airgap is distributed in both centerleg as return legs. This is no problem. Try to limit the wall thickness of the plastics and try to position the transmitter/reciever are accurate as possible. What you have to do is build a circuit on the primary side which detects the receiver part (increase of inductance). This is the challanging part. I would seek for cores used in planar transformers as they are very low in height and have huge cross sections.

     

    Best regards,

     

    Enrico Migchels

    Power Conversion Design Engineer

    Best - The Netherlands

    www.heliox.nl

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  • enrico.migchels
    0 enrico.migchels over 15 years ago
    This was found in an Interplak Model PB-12 electric toothbrush but similar designs are used in other appliances that need to be as tightly sealed as possible.

    A coil in the charging base (always plugged in and on) couples to a mating coil in the hand unit to form a step down transformer. The transistor, Q1, is used as an oscillator at about 60 kHz which results in much more efficient energy transfer via the air core coupling than if the system were run at 60 Hz. The amplitude of the oscillations varies with the full wave rectifier 120 Hz unfiltered DC power but the frequency is relatively constant.

         E1           CR2          R1                                E3
      AC o----+----+--|>|-----+---/\/\---+----+----------------+-------+  Coupling
              |   ~|  CR1     |+   1K    |    |                |        ) Coil
            +-+-+  +--|<|--+  |          |    / R2             |        ) 200T
        RU1 |MOV|     CR3  |  |      C1 _|_   \ 390K           |        ) #30
            +-+-+  +--|>|--|--+   .01uF ---   /          CR5   |     E4 ) 1-1/2"
           E2 |    |  CR4  |       250V  |    \ MPSA +---|<|---|----+--+   
      AC o----+----+--|<|--+             |    |   44 |         |    |
                  ~        |-     R3     |    | Q1 |/ C    C3 _|_  _|_ C2
                           +-----/\/\----+----+----|     .1uF ---  --- .0033uF
          CR1-CR4: 1N4005  |     15K               |\ E  250V  |    |  250V
                           |                R4       |         |    |
                           +---------------/\/\------+---------+----+
                                            1K
    
    
    The battery charger is nothing more than a diode to rectifier the signal coupled from the charging base. Thus, the battery is on constant trickle charge as long as the hand unit is set in the base. The battery pack is a pair of AA NiCd cells, probably about 500 mA-h.

    For the toothbrush, a 4 position switch selects between Off, Low, Medium, and High (S1B) and another set of contacts (S1A) also is activated by the same slide mechanism. The motor is a medium size permanent magnet type with carbon brushes.

                                           S1B
                                  S1A  +--o->o
                     D1           _|_  |       R1,15,2W
                 +---|>|---+------o o--+   L o---/\/\---+
        Coupling |         |                   R2,10,2W |
           Coil  +        _|_ BT1          M o---/\/\---+
           120T (          _  2.4V                      |
            #30 (         ___ .5A-h        H o----------+
         13/16"  +         _                            |
                 |         |        +-------+           |
                 +---------+--------| Motor |-----------+
                                    +-------+
    
    
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  • Former Member
    0 Former Member over 15 years ago in reply to enrico.migchels

    Hi Enrico!

     

    Thank you for your input!

     

    Yes, I did also find this example. :-)

    I have now started with the design. I will try to feed the charger with 24VDC so I can use an "off-the shelf" walladapter to supply the charger. It's also easier to work with and build up prototypes and measure on.

    I have added a 40 kHz oscillator since the inductor I have chosen is optimized for 40 kHz. I also think this is a nice frequency to work with since it will not cause too much trubbel with EMC and approval.

     

    Once I have a good "transmitter" I think the receiver will not be too difficult to build. In the end of the day the complete design might turn out to not be very complicated at all.

     

    It would be very nice to have a detection circuit as you suggest, but I guess that have to wiat until step 2. The primary goal is to proof that we can build an resonable effective inductive charger. When it works fine we might move on to step two which can be a detection circuit. I think the detection circuit can be done in different ways. CHange of inductance is one way. Simple radio transmitting is an other way. Light (infrared) indication is also an alternative.

    I guess not having a detection circuit at all can also be an alternative.

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  • enrico.migchels
    0 enrico.migchels over 15 years ago in reply to Former Member

    Hi Roger,

     

    Be carefull building circuits with free running oscillators, these devices are known to overheat in low load condictions. This is also the case when the inductance of the primary coil drops (receiver removed). The switching frequency rises to such high values that the switching losses can overheat the switching devices. I think a better approach is using a dedicated quasi resonant flyback controller (such as On semiconducter NCP1207). This controller limits the maximum switching frequency and has additional benefits. Additional to your primary winding should be a second winding which acts as a demagnetization detection and supply voltage. This winding is also in the transmitter part. In your case (as a feedback circuit to monitor the output voltage is missing), this winding tells you what voltage is on the secondary winding (ratio aux /sec winding). An even bigger advantage is that these devices have a high voltage current source (to startup from the mains supply voltage) and switch off  when the voltage on the VCC pin reaches a certain value. In your case the voltage on the VCC pin can only reach a steady value if the receiver is attached and therefore you have a detection circuit (receiver attached or not). There are still a few difficulties. Due to the bad coupling betrween primary and secondary winding the voltage on the output is not exactly similar to the ratio between aux/sec. Also the drop in inductance (receiver gone) is tricky, however the maximum current trough the winding is limited by the controller (there is a primary peak current detection on the controller). Look at the datasheet, there are also application examples.

     

    Best regards,

     

    Enrico Migchels

    Power Conversion Design Engineer

    Heliox B.V.

    Best - The Netherlands

    www.heliox.nl

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  • Former Member
    0 Former Member over 15 years ago in reply to enrico.migchels

    Hi Enrico!

     

    You are very helpful. Thanks a lot!

     

    I have done some calculations today and to me it doesn't look very good. If you have time maybe you can check if there is a major error in my calculations.

     

    The reaktans in an inductor is: 2 x pi(3.14) x frequency x L (in henry)

    With frequency of 40 kHz and a coil of 1000uH this gives 251.1 Ohm

     

    If I connect to mains (230VAC) and rectify I will get approx 330VDC.

    330V / 251 Ohm gives a current of 1.31A

     

    The energy in an inductor is calculated with formula: W=L x 0.5 x I x I

    In my example it gives 1000uH x 0.5 x 1.31 x 1.31 = 0.86mW

     

    Assuming that I have no losses when transfer energy from one inductor to the second one it would mean that I one the receiver side also have 0.86 W. I'm looking for 6V on the second side, and with those figures I will only get 0.14 mA at 6V.

     

    I need approx 1000 times more power still assuming that I have no losses.

     

    Hmmm, I realize that calculating inductors is not my strong side. I will go back and check with my old schoolbooks because this can't be right.

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  • enrico.migchels
    0 enrico.migchels over 15 years ago in reply to Former Member

    Hi there Roger,

     

    Luckely for you your situation isn't that bad. The output power for a flyback converter is given by the following formula:

     

    Pout=0.5 x Ip^2 x Lp x fs

    Ip = primary peakcurrent set by sense-resistor in source of FET, Ip= 1V/Rsense, 1V is the level given by the controller datasheet).

    Lp is the primary inductace of your flyback transformer,

    fs = switching frequency.

     

    For the input power (pushed into the core) you should calculate with a factor Pout/0.85 (85% efficiency assumed).

     

    For the following example: Ip = 3A and Fs, min = 40kHz, Lp = 500uH, your output power is 90W.

     

    Note that increasing the peak current increases the output power fast, but take care that the ferrite core can not be exited more than 300mT, otherwise you will saturate the ferrite.

     

    Best regards,

     

    Enrico Migchels

    Power Supply Design Engineer

    Best - The Netherlands

    www.heliox.nl

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  • Former Member
    0 Former Member over 15 years ago in reply to enrico.migchels

    Hello,

     

     

    I am interested in the " Electric Toothbruh Inductively Coupled Charger " schematics.

     

    Please let me know if someone has tested this circuit.

     

    Does it work well without a magnetic core coupling ( and only with a air core coupling ) ?

     

     

    Thanks in advance

     

    Best regards

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