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Arduino Forum Getting rid of batteries... simple question but what is the best way ?
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Related

Getting rid of batteries... simple question but what is the best way ?

redgreenblue
redgreenblue over 8 years ago

Hi Guys !

 

I have 4 door sensors with an arduino to have a simple sound trigger but also calculated how much peoples are getting by (helping a small museum in town).  I'll skip the details but the thing is I need to make theses connected to DC to avoid batteries changes (staff too busy). I figure the simple way to do it is using the arduino voltage out to the sensors.

 

I find this simple question complicated becuz I wonder if the current drain from the arduino will be enough for 4 sensors, so does capacitor might do the trick or if this is not the way to do it, I wonder if the AMP from the power supply should be higher ?

 

My calculation are that each sensor need 2x 1.5 volt batteries so it's approx. 3 volt @ 500mA

But I've tried the arduino output and 3.3volt does the trick, very good with one device.

 

Here a quick diagram of the setup.

If there is an expert in the room, stand up !

 

thank for your support

Element 14 is GREAT !!

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  • jw0752
    jw0752 over 8 years ago +2 suggested
    Hi, Can you give us a little more information on your sensors? The 500 mA seems awful high for a simple sensor. Do these devices light, ring or buzz? Are they being used as inputs to the Arduino. The 3…
  • jw0752
    jw0752 over 8 years ago in reply to redgreenblue +1 suggested
    Hi redgreenblue, Without knowing more details I would bring power from a separate 3 volt power supply and not try to use the 3.3 volts available on the Arduino. You could do this by having a separate wall…
  • jw0752
    jw0752 over 8 years ago in reply to redgreenblue +1 suggested
    Hi, Units that have 2 AA batteries for a power source will likely be designed to operate on much lower current draw than 500 mA. If not you would be replacing the batteries daily. AA batteries can deliver…
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  • redgreenblue
    0 redgreenblue over 8 years ago

    Hey John, it worked, I'm happy to have discover something very usefull, the only thing is that I don't have mA option on my multimeter (not sure on drawing if this is what you meant),

     

    so I put it to 10A which was anyway the only one I got a reading.

    It gave me 0.01, so does this mean I need to X10 times becuz it was on 10A selection...

    in other words it might be 0.100 mA if this is the right way to do this... ?

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  • jw0752
    0 jw0752 over 8 years ago in reply to redgreenblue

    Hi redgreenblue,

     

    dougw   is correct about the 10 mA but due to the Scale that you are using we may be as high as 15 mA or as low as 6 mA as your meter would not show the next digit and probably rounds off. Also follow through and trigger the alarm and take a reading as Doug has suggested as this will likely give a higher current draw. Other than that you did the correct thing when you chose the A scale on the meter.

     

    John

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  • jw0752
    0 jw0752 over 8 years ago in reply to redgreenblue

    Hi redgreenblue,

     

    dougw   is correct about the 10 mA but due to the Scale that you are using we may be as high as 15 mA or as low as 6 mA as your meter would not show the next digit and probably rounds off. Also follow through and trigger the alarm and take a reading as Doug has suggested as this will likely give a higher current draw. Other than that you did the correct thing when you chose the A scale on the meter.

     

    John

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