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Arduino Forum Detecting OFF state of an AC Load
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Related

Detecting OFF state of an AC Load

anishkgt
anishkgt over 8 years ago

Hi All,

 

I am trying to switch on a LOAD from its OFF state by detecting a change in the voltage. Here the load is a MOT, the voltage at the primary is 1VAC when OFF.

 

My idea is to switch ON the MOT by detecting the voltage change at the primary when the Secondary are shorted. I can see a voltage drop of .5VAC when shorted. How can i monitor this voltage change with an Arduino.

 

My solution to the problem is shown below.

image

The Live of mains is connected to the MOT through the LIVE_LOAD in the schematic. During the OFF state the Optocoupler is triggered so that the 1VAC is seen by the Precision rectifier LT1078 and is rectified and send to the Analog pin A0 on the Arduino. With a code i could detect the voltage change and use it trigger the MOT again and at the same disable the optocoupler to break the circuit to the LT1078. Basically eliminating the need to press a switch two switch ON the MOT.

 

is there a better way to get this done. I was thinking of using the basic 1N4007 to convert the 1VAC to dc but that would be a problem when the MOT is switched ON allowing the mains 240VAC to flow through the DIODE.

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  • dougw
    dougw over 8 years ago in reply to anishkgt +4 suggested
    1.3 V rms rectified is 1.8 Vdc minus the drop in a lightly loaded Schottky diode of 0.3 V is 1.5 V dc peak. The zener on the Schottky diode output is just to clamp the signal so it doesn't exceed your…
  • shabaz
    shabaz over 8 years ago in reply to anishkgt +4
    Electrodes? Important information like this is kind of missing in your question.. If you provide half the information, it's not a surprise that it wasn't understandable.
  • shabaz
    shabaz over 8 years ago +3 suggested
    The question (and the circuit) is not understandable I think : ( Could you rephrase the question, or draw a block diagram? The circuit doesn't make sense.
  • dougw
    0 dougw over 8 years ago in reply to anishkgt

    Its getting better but C4 still would need to be a high voltage part.

    If you take R2 away (open circuit), short out R1 (and remove it), and make R4 at least 100K then C4 can be a low voltage part.

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  • anishkgt
    0 anishkgt over 8 years ago in reply to dougw

    dougw  wrote:

     

    Its getting better but C4 still would need to be a high voltage part.

    Yes it is 10uf 400V. But removing R2 would give a bit of a distortion on the wave form and it would get even worse without R1.

    image

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  • anishkgt
    0 anishkgt over 8 years ago in reply to anishkgt

    i was looking at this diode and i read that at 10A there would be a voltage drop of 1.18v. So if i understand, it would be even lower for this application making it a good choice ?

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  • anishkgt
    0 anishkgt over 8 years ago

    I have just tested this out and it does not seem to get what i thought it would. The output from the zener is square wave. but on the ADC it seems to be oscillating.

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  • anishkgt
    0 anishkgt over 8 years ago in reply to anishkgt

    image

    This seems to be a better design but need some help to pull the output to gnd when the Vin is greater than the reference (0.2v). Then

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  • anishkgt
    0 anishkgt over 8 years ago in reply to anishkgt

    image

    Seems to have nailed it.

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