Using the ARC command

Victor Fraenckel schrieb:

I have spent yesterday afternoon and this morning trying to understand how

to use the ARC command on the command line with no luck. All I want to do

is to draw and arc of radius 0.5" centered at 0.5", 1.7" with a specific

line width.

 

The eagle manual is of no help because the description of the command is

too cryptic for me to understand. Can anyone help me understand how to do

this?

Did you also have a loop at HELP ARC, and did you realize how manually

drawing ARCs works?

You need to know that the command line syntax exactly follows the "mouse

click syntax". At the command line, you simply provide coordinates as if

they were clicked by mouse.

You need to provide three coordinates: The first is the beginning of the

ARC, the second is exactly the opposite side of the ARC (say, at 180

degrees) - so your "center" coordinate is defined as the position right

(centered) between those two coordinates.

The third coordinate, finally, defines the angle of the ARC (related to

the center) - regardless if it's on the ARC diameter or not.

So, if you enter

     ARC 0.1 (-1 0) (1 0) (1 1);

you'll get an ARC of width 0.1, starting at (-1 0) which is the first

given coordinate, centered at (0 0) which is exactly halfway between the

first two coordinates, and ending at 45 degrees (defined by the third

coordinate).

You didn't mention starting and ending angle of the ARC you need, so I

can't provide a working command for your particular need. However,

assuming you need a 180° arc, the command would look like:

     grid inch;

     arc  (0 1.7) (1 1.7) (1 1.7);

You can specify the direction of the ARC with "CW" and "CCW" parameters.

Tilmann

Victor Fraenckel schrieb:

I have spent yesterday afternoon and this morning trying to understand how

to use the ARC command on the command line with no luck. All I want to do

is to draw and arc of radius 0.5" centered at 0.5", 1.7" with a specific

line width.

 

The eagle manual is of no help because the description of the command is

too cryptic for me to understand. Can anyone help me understand how to do

this?

Did you also have a loop at HELP ARC, and did you realize how manually

drawing ARCs works?

You need to know that the command line syntax exactly follows the "mouse

click syntax". At the command line, you simply provide coordinates as if

they were clicked by mouse.

You need to provide three coordinates: The first is the beginning of the

ARC, the second is exactly the opposite side of the ARC (say, at 180

degrees) - so your "center" coordinate is defined as the position right

(centered) between those two coordinates.

The third coordinate, finally, defines the angle of the ARC (related to

the center) - regardless if it's on the ARC diameter or not.

So, if you enter

     ARC 0.1 (-1 0) (1 0) (1 1);

you'll get an ARC of width 0.1, starting at (-1 0) which is the first

given coordinate, centered at (0 0) which is exactly halfway between the

first two coordinates, and ending at 45 degrees (defined by the third

coordinate).

You didn't mention starting and ending angle of the ARC you need, so I

can't provide a working command for your particular need. However,

assuming you need a 180° arc, the command would look like:

     grid inch;

     arc  (0 1.7) (1 1.7) (1 1.7);

You can specify the direction of the ARC with "CW" and "CCW" parameters.

Tilmann