Hello,
I need to create this land pattern from the figure attached, but I couldn´t.
Has anyone seen this land pattern? It is from a demodulator.
thanks
Thiago
Attachments:
 |
Hello,
I need to create this land pattern from the figure attached, but I couldn´t.
Has anyone seen this land pattern? It is from a demodulator.
thanks
Thiago
|
Thiago wrote:
"Eric Agan" <eric@elegantinvention.com> escreveu na mensagem
news:g3u4vd$473$1@cheetah.cadsoft.de...
Thiago wrote:
Hello,
I need to create this land pattern from the figure attached, but I
couldn´t. Has anyone seen this land pattern? It is from a demodulator.
thanks
Thiago
Could you be more specific, what do you mean by you couldn't?
Eric Agan
Well, I think it is missing some measures.... I don´t have too much
experience with land pattern creation... I know the basics... Is there any
adjustments that I could do to make this design easier?
Looks like you would have four pads of size 1.7x1.3 at each corner.
EAGLE places pads on center, but this diagram shows their locations at
the edges, so just do a bit of math: We know that from the bottom edge
of the pad to the center is 3.3 (half of the 6.6 from pad-to-pad that is
shown on the package diagram). Add half the height of the pad, so 1.7/2
= 0.85, and you get 0.85 + 3.3 = 4.15, so that's our Y coordinate for
the corner pads (and -4.15 for the bottom ones, of course). The X
coordinate can be had in the same fashion: the diagram shows 9.4 from
inner edge to inner edge, just like before. So it's 9.4 / 2 = 4.7 from
the edge of one to the center, and again add half the length so 4.7 +
(1.3 / 2) = 5.35, so the X coordinate is 5.35 
So your corner pads get
placed at (5.35 4.15), (5.35, -4.15), (-5.35, 4.15), and (-5.35, -4.15).
As for the other pads, they're 0.6x1.5 it looks like, and they're at
1.0mm pitch. So we know they're 1.0 apart, and we have their size, only
thing left is how far each row/column is from the center. The diagram
shows that the two rows (top and bottom) are 8.8 away at the inner
edges, so we know the inner is 4.4 from the center. Just like before we
add half the length of the pad and we get 4.4 + (1.5/2) = 5.15 for our Y
coordinate (and -5.15 for the bottom row). So, simply place them at (0,
5.15), (1, 5.15), (2, 5.15), ... etc.
The columns are spaced 9.0 apart (inner edge to inner edge), so same
things goes (9.0/2) + (1.5/2) = 5.25 for the X coordinate, and we
increment Y by 1 each time (remember, 1mm pitch). Place those at (5.25,
0), (5.25, 1), etc...
Hope that explains it,
Eric Agan
"Eric Agan" <eric@elegantinvention.com> escreveu na mensagem
news:g3u6rj$9pl$1@cheetah.cadsoft.de...
Thiago wrote:
"Eric Agan" <eric@elegantinvention.com> escreveu na mensagem
news:g3u4vd$473$1@cheetah.cadsoft.de...
Thiago wrote:
Hello,
I need to create this land pattern from the figure attached, but I
couldn´t. Has anyone seen this land pattern? It is from a demodulator.
thanks
Thiago
Could you be more specific, what do you mean by you couldn't?
Eric Agan
Well, I think it is missing some measures.... I don´t have too much
experience with land pattern creation... I know the basics... Is there
any
adjustments that I could do to make this design easier?
Looks like you would have four pads of size 1.7x1.3 at each corner. EAGLE
places pads on center, but this diagram shows their locations at the
edges, so just do a bit of math: We know that from the bottom edge of the
pad to the center is 3.3 (half of the 6.6 from pad-to-pad that is shown on
the package diagram). Add half the height of the pad, so 1.7/2 = 0.85, and
you get 0.85 + 3.3 = 4.15, so that's our Y coordinate for the corner pads
(and -4.15 for the bottom ones, of course). The X coordinate can be had in
the same fashion: the diagram shows 9.4 from inner edge to inner edge,
just like before. So it's 9.4 / 2 = 4.7 from the edge of one to the
center, and again add half the length so 4.7 + (1.3 / 2) = 5.35, so the X
coordinate is 5.35
So your corner pads get placed at (5.35 4.15),
(5.35, -4.15), (-5.35, 4.15), and (-5.35, -4.15).
As for the other pads, they're 0.6x1.5 it looks like, and they're at 1.0mm
pitch. So we know they're 1.0 apart, and we have their size, only thing
left is how far each row/column is from the center. The diagram shows that
the two rows (top and bottom) are 8.8 away at the inner edges, so we know
the inner is 4.4 from the center. Just like before we add half the length
of the pad and we get 4.4 + (1.5/2) = 5.15 for our Y coordinate (and -5.15
for the bottom row). So, simply place them at (0, 5.15), (1, 5.15), (2,
5.15), ... etc.
The columns are spaced 9.0 apart (inner edge to inner edge), so same
things goes (9.0/2) + (1.5/2) = 5.25 for the X coordinate, and we
increment Y by 1 each time (remember, 1mm pitch). Place those at (5.25,
0), (5.25, 1), etc...
Hope that explains it,
Eric Agan
Ok Eric, thanks. I was kind of hoping to avoid all this by just doing the
correct adjustments on the grid, maybe.
Anyway, I´ll do the job by entering coordinates.
Thiago
