Hello,
I need to create this land pattern from the figure attached, but I couldn´t.
Has anyone seen this land pattern? It is from a demodulator.
thanks
Thiago
Attachments:
 |
Hello,
I need to create this land pattern from the figure attached, but I couldn´t.
Has anyone seen this land pattern? It is from a demodulator.
thanks
Thiago
|
Thiago wrote:
"Eric Agan" <eric@elegantinvention.com> escreveu na mensagem
news:g3u4vd$473$1@cheetah.cadsoft.de...
Thiago wrote:
Hello,
I need to create this land pattern from the figure attached, but I
couldn´t. Has anyone seen this land pattern? It is from a demodulator.
thanks
Thiago
Could you be more specific, what do you mean by you couldn't?
Eric Agan
Well, I think it is missing some measures.... I don´t have too much
experience with land pattern creation... I know the basics... Is there any
adjustments that I could do to make this design easier?
Looks like you would have four pads of size 1.7x1.3 at each corner.
EAGLE places pads on center, but this diagram shows their locations at
the edges, so just do a bit of math: We know that from the bottom edge
of the pad to the center is 3.3 (half of the 6.6 from pad-to-pad that is
shown on the package diagram). Add half the height of the pad, so 1.7/2
= 0.85, and you get 0.85 + 3.3 = 4.15, so that's our Y coordinate for
the corner pads (and -4.15 for the bottom ones, of course). The X
coordinate can be had in the same fashion: the diagram shows 9.4 from
inner edge to inner edge, just like before. So it's 9.4 / 2 = 4.7 from
the edge of one to the center, and again add half the length so 4.7 +
(1.3 / 2) = 5.35, so the X coordinate is 5.35 
So your corner pads get
placed at (5.35 4.15), (5.35, -4.15), (-5.35, 4.15), and (-5.35, -4.15).
As for the other pads, they're 0.6x1.5 it looks like, and they're at
1.0mm pitch. So we know they're 1.0 apart, and we have their size, only
thing left is how far each row/column is from the center. The diagram
shows that the two rows (top and bottom) are 8.8 away at the inner
edges, so we know the inner is 4.4 from the center. Just like before we
add half the length of the pad and we get 4.4 + (1.5/2) = 5.15 for our Y
coordinate (and -5.15 for the bottom row). So, simply place them at (0,
5.15), (1, 5.15), (2, 5.15), ... etc.
The columns are spaced 9.0 apart (inner edge to inner edge), so same
things goes (9.0/2) + (1.5/2) = 5.25 for the X coordinate, and we
increment Y by 1 each time (remember, 1mm pitch). Place those at (5.25,
0), (5.25, 1), etc...
Hope that explains it,
Eric Agan
Thiago wrote:
"Eric Agan" <eric@elegantinvention.com> escreveu na mensagem
news:g3u4vd$473$1@cheetah.cadsoft.de...
Thiago wrote:
Hello,
I need to create this land pattern from the figure attached, but I
couldn´t. Has anyone seen this land pattern? It is from a demodulator.
thanks
Thiago
Could you be more specific, what do you mean by you couldn't?
Eric Agan
Well, I think it is missing some measures.... I don´t have too much
experience with land pattern creation... I know the basics... Is there any
adjustments that I could do to make this design easier?
Looks like you would have four pads of size 1.7x1.3 at each corner.
EAGLE places pads on center, but this diagram shows their locations at
the edges, so just do a bit of math: We know that from the bottom edge
of the pad to the center is 3.3 (half of the 6.6 from pad-to-pad that is
shown on the package diagram). Add half the height of the pad, so 1.7/2
= 0.85, and you get 0.85 + 3.3 = 4.15, so that's our Y coordinate for
the corner pads (and -4.15 for the bottom ones, of course). The X
coordinate can be had in the same fashion: the diagram shows 9.4 from
inner edge to inner edge, just like before. So it's 9.4 / 2 = 4.7 from
the edge of one to the center, and again add half the length so 4.7 +
(1.3 / 2) = 5.35, so the X coordinate is 5.35 So your corner pads get
placed at (5.35 4.15), (5.35, -4.15), (-5.35, 4.15), and (-5.35, -4.15).
As for the other pads, they're 0.6x1.5 it looks like, and they're at
1.0mm pitch. So we know they're 1.0 apart, and we have their size, only
thing left is how far each row/column is from the center. The diagram
shows that the two rows (top and bottom) are 8.8 away at the inner
edges, so we know the inner is 4.4 from the center. Just like before we
add half the length of the pad and we get 4.4 + (1.5/2) = 5.15 for our Y
coordinate (and -5.15 for the bottom row). So, simply place them at (0,
5.15), (1, 5.15), (2, 5.15), ... etc.
The columns are spaced 9.0 apart (inner edge to inner edge), so same
things goes (9.0/2) + (1.5/2) = 5.25 for the X coordinate, and we
increment Y by 1 each time (remember, 1mm pitch). Place those at (5.25,
0), (5.25, 1), etc...
Hope that explains it,
Eric Agan
