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Forum Multi (wide) Voltage LED using LM317
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  • current
  • regulator
  • constant
Related

Multi (wide) Voltage LED using LM317

Malcolm
Malcolm over 16 years ago
Just a thought, we know you can change a linear voltage regulator like the LM317 into a series constant current regulator by just adding one resistor (loads of application notes on Farnell Web site) but can it be done with the LM431 adjustable shunt regulator?
Anyone know?

 

Regs (regards not regulator)

Malcolm

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  • Former Member
    0 Former Member over 16 years ago

    ,image

    This above picture is the typical application circuit of LM431, it shows us how to adjust VKA. If we replace R1 with LEDs, LEDs current will be adjusted by R2 and Vref. If  Vref and R2 is constant, LEDs current will be constant too

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  • Former Member
    0 Former Member over 16 years ago

    ,image

    This above picture is the typical application circuit of LM431, it shows us how to adjust VKA. If we replace R1 with LEDs, LEDs current will be adjusted by R2 and Vref. If  Vref and R2 is constant, LEDs current will be constant too

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  • kemmi
    0 kemmi over 16 years ago in reply to Former Member

    Switching Regulator.JPG

    From  efficiency point, maybe only LM431 is not a good solution because input resistor will share more power dissipation.

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  • Former Member
    0 Former Member over 16 years ago in reply to kemmi

    Good solution. But the circuit is too complex. Especially the chopper is hard to adjust.

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  • Malcolm
    0 Malcolm over 16 years ago in reply to Former Member

    Constant Current with one resistor.bmp

     

     

     

     

    This is the circuit I would normally use to generate a constant current of about 25mA. The input voltage is anything up to 37volts. The required resistor is calculated (roughly) by 1.2 volts divided by the current required. Eg 1.2V/.025A= about 47 ohms Resistor power is  Voltage squared/Resistance (eg 1.2*1.2/47ohms = 30mW)  OR  Current*Current*Resistance The power disipitation in the LM317 is of course the voltage drop across it multiplied by the current flowing through it (eg same current as going through your LED, "current through a series circuit is the same")

    NOTE:-47 ohm resistor used

    LM317 (small TO-92 packages)  http://uk.farnell.com/jsp/search/browse.jsp;jsessionid=BBVYM0BUEM3HMCQLCIPZK0Q?N=551&Ntk=gensearch_001|gensearch_001&Ntt=lm317|to-92&Ntx=&displaytext=&_requestid=163594

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  • kemmi
    0 kemmi over 16 years ago in reply to Malcolm

    your solution is only for small power LED driver.How about Power LED(350mA current or more ) for resistor will result in lower efficiency

     

    ???.JPG

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  • Former Member
    0 Former Member over 16 years ago in reply to kemmi

    In fact, your solution is a series regulator with discrete parts. The transistor will consume power like the resistance does in my solution. I agree that my solution is suitable for low power led only. For high power led application, I'd like to choose Malcolm's LM317 solution.

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  • Former Member
    0 Former Member over 15 years ago in reply to Malcolm

          Hello!

    If a 24VAC power supply, can be solved with the LM317 and the MOSFET controller. The solution is to link http://www.sper.hr/eng/wld.htm.Works for years. No inductors. Effiency about 70%. It can be used 1..8 LED.                         
    Attachments:
    image
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  • Jason
    0 Jason over 15 years ago in reply to Former Member

    I don't think using a series regulator (LDO or some discrete parts) is a good idear for hight power LED(typical 350mA). we can count the power dissipation as Pd=350mA*(V_in-V_led).if we use a Multi (wide) Voltage,V_in-V_led will very large,that means we need a high power dissipation component and more heat-sink and more cost but low efficiency.by the way ,how can we desgn for the constant current control,it's another cost.

    If we using switch regulator ,the issue above is not a problem.You will say what about the cost? infact,a switch regulator is expensive than LDO,but you can compare the total cost as the same function you need(CC control,dimming,open/short protect e.g.),what is the result you've got?image

    But in some special application we can use series regulator for power LED,like the fixed DC input.we can design the V_in-V_led very small for decrease Pd.maybe LM317 is a good choose image

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  • Former Member
    0 Former Member over 15 years ago in reply to Jason
    I agree that the circuit with MOSFET and LM317 expensive, but there are advantages. It is suitable for amateur implementation. Voltage on the LM317 is only 2V, and the average voltage on the IRF540 (when I> 0) is the same. Circuit has a lot of parts takes place, but the Rolls-Royce in quality and durability. It is suitable for industrial applications where reliability is important. Scheme http://www.sper.hr/eng/64071150.gif
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