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EAGLE User Support (English) AC mains on a PCB ?
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Related

AC mains on a PCB ?

anishkgt
anishkgt over 9 years ago

A total newbie to eagle design and PCB fab. So plase bear with on my silly questions, trying to learn.

 

I have pcb that is schematically completed with the layout. Before i start the fabrication process i need some expert advise if the components placed and the wires routed are ok for the ac mains and the others. The load here will be a transformer. The ac mains are 240VAC and all works well as designed in the schematic on a bread broad except for the load for which MOC3023 is yet to arrive from where i've ordered.

 

 

 

Thanks in advance.

 

image

 

image

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  • rachaelp
    rachaelp over 9 years ago in reply to anishkgt +2
    Hi George, It looks like you're really learning a lot with this design and you've had lots of good advice from people on this thread already and the difference between the initial version you posted and…
  • michaelkellett
    michaelkellett over 9 years ago in reply to rachaelp +1 suggested
    For mains input spike suppression I think you are much better off with this kind of device: http://uk.farnell.com/epcos/b72214s0231k101/varistor-60-0j-230vac/dp/1004389 Farnell 1004389 This one is rated…
  • autodeskguest
    autodeskguest over 9 years ago in reply to anishkgt +1 suggested
    On 11/09/16 12:02, George Thomas wrote: Why two thrustirs to control the load and am trouble witching on yhe Triac. Triacs can suffer commutation problems with certain types of load - highly inductive…
Parents
  • anishkgt
    0 anishkgt over 9 years ago

    How can the trace be routed without breaking the clearance rules from IC4 to IC1 ? maybe a jumper

     

    What would be the need for the resistor between IC4 and IC1, like a current limiter so it does not short out? Yes, its an ATmega328P Microcontroller.

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  • anishkgt
    0 anishkgt over 9 years ago

    How can the trace be routed without breaking the clearance rules from IC4 to IC1 ? maybe a jumper

     

    What would be the need for the resistor between IC4 and IC1, like a current limiter so it does not short out? Yes, its an ATmega328P Microcontroller.

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  • autodeskguest
    0 autodeskguest over 9 years ago in reply to anishkgt

    On 15.09.2016 12:53, George Thomas wrote:

    How can the trace be routed without breaking the clearance rules from IC4 to IC1 ? maybe a jumper

     

    What would be the need for the resistor between IC4 and IC1, like a current limiter so it does not short out? Yes, its an ATmega328P Microcontroller.

     

    If he's in control over the firmware, maybe the IO's can be swapped

    around a bit to allow routing to the closer IO's of IC1. I don't know if

    any of the selected IO's have special functions needed.

     

     

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  • anishkgt
    0 anishkgt over 9 years ago in reply to autodeskguest

    There are only two pins that has the interrupt that is Pin4 and Pin5. Mentioned here. The Pin4 gets the zero crossing from IC4 and send into the pin4 of IC1.

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  • autodeskguest
    0 autodeskguest over 9 years ago in reply to anishkgt

    On 15.09.2016 13:41, George Thomas wrote:

    There are only two pins that has the interrupt that is Pin4 and Pin5. Mentioned here (https://www.arduino.cc/en/uploads/Hacking/Atmega168PinMap2.png). The Pin4 gets the zero crossing from IC4 and send into the pin4 of IC1.

     

     

    Fair enough image

     

    How about swapping space on IC4 and the bridge rectifier and move the

    buzzer away a bit? Imagine pulling the "rope" on this crossover signal

    and push the reg down below IC1, powering it in a vertical line up from

    the middle.

     

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  • michaelkellett
    0 michaelkellett over 9 years ago in reply to anishkgt

    The resistor would have no useful electrical function, it is just intended as mechanical link.

     

    MK

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  • anishkgt
    0 anishkgt over 9 years ago in reply to michaelkellett

    no electrical link but a mechanical link ????? what does that mean ? wouldn't it act like current limiting resistor.

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  • michaelkellett
    0 michaelkellett over 9 years ago in reply to anishkgt

    The input of the micro is quite a high impedance so putting a 10R (or 100R resistor in series will have no detectable effect.

     

    You ought to move D1 down a little since it is now the closest thing on the low voltage side to the mains.

     

    For safety the ground plane (polygon) should be very solidly connected to mains earth - then if you do get a short on your board the dangerous current will flow to earth rather than though you.

     

    MK

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  • rachaelp
    0 rachaelp over 9 years ago in reply to anishkgt

    George Thomas wrote:

     

    no electrical link but a mechanical link ????? what does that mean ? wouldn't it act like current limiting resistor.

    Use a 0R resistor, or just a wire jumper.

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  • autodeskguest
    0 autodeskguest over 9 years ago in reply to michaelkellett

    On 15.09.2016 16:57, Michael Kellett wrote:

    The input of the micro is quite a high impedance so putting a 10R (or 100R resistor in series will have no detectable effect.

     

    You ought to move D1 down a little since it is now the closest thing on the low voltage side to the mains.

     

    For safety the ground plane (polygon) should be very solidly connected to mains earth - then if you do get a short on your board the dangerous current will flow to earth rather than though you.

     

    The design looks earthless (isoladed AC). I don't know if there are any

    compliance rules that says you need to do that, but the fact that the

    LOAD is ext to pcb, and you are probably exposing the LOAD AC contacts

    for spot welding, makes me thing you do need it. Maybe it even requires

    isolated high voltage there, wich would make this design require an

    isolating 1:1 transformer in front.

     

     

     

     

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  • autodeskguest
    0 autodeskguest over 9 years ago in reply to michaelkellett

    On 15.09.2016 16:57, Michael Kellett wrote:

    The input of the micro is quite a high impedance so putting a 10R (or 100R resistor in series will have no detectable effect.

     

    You ought to move D1 down a little since it is now the closest thing on the low voltage side to the mains.

     

    For safety the ground plane (polygon) should be very solidly connected to mains earth - then if you do get a short on your board the dangerous current will flow to earth rather than though you.

     

    The design looks earthless (isoladed AC). I don't know if there are any

    compliance rules that says you need to do that, but the fact that the

    LOAD is ext to pcb, and you are probably exposing the LOAD AC contacts

    for spot welding, makes me thing you do need it. Maybe it even requires

    isolated high voltage there, wich would make this design require an

    isolating 1:1 transformer in front.

     

     

     

     

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